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3 years ago

(28 POINTS)

Mathematics

1 answer:

cestrela7 [59]3 years ago

3 0

Answer:

(a) $-\sqrt{10}y$

(b) $-\sqrt{3}y$

Step-by-step explanation:

(a) $\sqrt{10y^{2}}$ can also be written as $\sqrt{10}$ x $\sqrt{y^{2}}$

the $\sqrt{y^{2}}$ = ± y

Therefore :

$\sqrt{10y^{2}}$ = ± $\sqrt{10}y$

since it was given that y < 0 , then the factor will be $-\sqrt{10}y$

(b) $\sqrt{3y^{2}}$ can also be written as : $\sqrt{3}$ x $\sqrt{y^{2}}$

Therefore , one of the factor is $-\sqrt{3}y$

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Step-by-step explanation:

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