Answer:
Midpoint (x , y) of two points is
( x1 + y1/2 , x2 + y2/2)
Midpoint of KL is M ( -8 , 1)
Let the coordinates of L be ( a , b)
From the above definition
Midpoint between K(-6 , 5) and
L ( a ,b) is
(-8 , 1) = ( -6+a/2 , 5+b/2)
Comparing first point with - 8
- 8 = -6 + a /2
Multiply through by 2
We get
-16 = - 6 + a
a = -16+6
a = - 10
Comparing the second point with 1
1 = 5+b/2
Multiply through by 2
2 = 5 + b
b = 2 - 5
b = -3
Therefore a = -10 and b = - 3
Hence the coordinates of
L is ( -10 , - 3)
Hope this helps
Answer:
28.28(simplified from 28.2743338834)
Step-by-step explanation:
area of sector= (center angle/360)*area of circle
we are already given the area of sector as 3/2pi
so
3/2pi=(60/360)*x
(x is area of circle)
3/2pi=4.71238898038
4.71238898038=1/6x
divide both sides by "1/6"
28.2743338834=x
hope this helps!
I think it’s A
Sorry if I’m wrong
Answer: sin u = -5/13 and cos v = -15/17
Step-by-step explanation:
The nice thing about trig, a little information goes a long way. That’s because there is a lot of geometry and structure in the subject. If I have sin u = opp/hyp, then I know opp is the opposite side from u, and the hypotenuse is hyp, and the adjacent side must fit the Pythagorean equation opp^2 + adj^2 = hyp^2.
So for u: (-5)^2 + adj^2 = 13^2, so with what you gave us (Quad 3),
==> adj of u = -12 therefore cos u = -12/13
Same argument for v: adj = -15,
opp^2 + (-15)^2 = 17^2 ==> opp = -8 therefore sin v = -8/17
The cosine rule for cos (u + v) = (cos u)(cos v) - (sin u)(sin v) and now we substitute: cos (u + v) = (-12/13)(-15/17) - (-5/13)(-8/17)
I am too lazy to do the remaining arithmetic, but I think we have created a way to approach all of the similar problems.
Answer:
Step-by-step explanation:
The top has area (3 cm)(5 cm), or: 15 cm^2
The bottom has the same area: 15 cm^2
Each of the ends has the area (3 cm)(2.5 cm): 7.5 cm^2
7.5 cm^2
Each of the sides has the area (2.5 cm)(5 cm) 12.5 cm^2
12.5 cm^2
-------------------
70 cm^2
The total lateral area is 70 cm^2
