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2 years ago

It’s a test question.

Mathematics

1 answer:

marissa [1.9K]2 years ago

4 0

Answer:

A # is odd

Step-by-step explanation:

Hypothesis-----> conclusion

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WILL GIVE A BRAINLEST

andreyandreev [35.5K]

Two end points
One direction

Hope this helps xx

5 0

3 years ago

in exercises 15-20 find the vector component of u along a and the vecomponent of u orthogonal to a u=(2,1,1,2) a=(4,-4,2,-2)

Nimfa-mama [501]

Answer:

The component of $\vec u$ orthogonal to $\vec a$ is $\vec u_{\perp\,\vec a} = \left(\frac{9}{5},\frac{6}{5},\frac{9}{10},\frac{21}{10}\right)$ .

Step-by-step explanation:

Let $\vec u$ and $\vec a$ , from Linear Algebra we get that component of $\vec u$ parallel to $\vec a$ by using this formula:

$\vec u_{\parallel \,\vec a} = \frac{\vec u \bullet\vec a}{\|\vec a\|^{2}} \cdot \vec a$ (Eq. 1)

Where $\|\vec a\|$ is the norm of $\vec a$ , which is equal to $\|\vec a\| = \sqrt{\vec a\bullet \vec a}$ . (Eq. 2)

If we know that $\vec u =(2,1,1,2)$ and $\vec a=(4,-4,2,-2)$ , then we get that vector component of $\vec u$ parallel to $\vec a$ is:

$\vec u_{\parallel\,\vec a} = \left[\frac{(2)\cdot (4)+(1)\cdot (-4)+(1)\cdot (2)+(2)\cdot (-2)}{4^{2}+(-4)^{2}+2^{2}+(-2)^{2}} \right]\cdot (4,-4,2,-2)$

$\vec u_{\parallel\,\vec a} =\frac{1}{20}\cdot (4,-4,2,-2)$

$\vec u_{\parallel\,\vec a} =\left(\frac{1}{5},-\frac{1}{5},\frac{1}{10},-\frac{1}{10} \right)$

Lastly, we find the vector component of $\vec u$ orthogonal to $\vec a$ by applying this vector sum identity:

$\vec u_{\perp\,\vec a} = \vec u - \vec u_{\parallel\,\vec a}$ (Eq. 3)

If we get that $\vec u =(2,1,1,2)$ and $\vec u_{\parallel\,\vec a} =\left(\frac{1}{5},-\frac{1}{5},\frac{1}{10},-\frac{1}{10} \right)$ , the vector component of $\vec u$ is:

$\vec u_{\perp\,\vec a} = (2,1,1,2)-\left(\frac{1}{5},-\frac{1}{5},\frac{1}{10},-\frac{1}{10} \right)$

$\vec u_{\perp\,\vec a} = \left(\frac{9}{5},\frac{6}{5},\frac{9}{10},\frac{21}{10}\right)$

The component of $\vec u$ orthogonal to $\vec a$ is $\vec u_{\perp\,\vec a} = \left(\frac{9}{5},\frac{6}{5},\frac{9}{10},\frac{21}{10}\right)$ .

4 0

2 years ago

Type no, one, or infinite to complete the statement. Type only lowercase letters. Do not type spaces in your answer. 3x - 4y = 6

julsineya [31]

Answer:infinite both can e simplifies

Step-by-step explanation:

3 0

3 years ago

Middle school math problem

irina [24]

Answer:

12%

Step-by-step explanation:

4 0

2 years ago

NO FAKE ANSWERS PLEASE IM BEGGING YOU 40 POINTS!!!!!! PLEEASEEEE HELP!!!!!!!!!!!!!! I already solved half of it pls help on part

Vikki [24]

Answer:

Part 1

Given equation:

C(t) = -0.30 (t – 12)² + 40

For t = 0

C(t) = -0.30 (0 - 12)² + 40

C(t) = -0.30 (-12)² + 40

C(t) = -3.2

For t = 12 (noon)

C(t) = -0.30 (12 - 12)² + 40

C(t) = -0.30 (0)² + 40

C(t) = 40

For t = 24 (midnight)

C(t) = -0.30 (24 - 12)² + 40

C(t) = -0.30 (12)² + 40

C(t) = -0.30 × 144 + 40

C(t) = - 43.2 + 40

C(t) = -3.2

Part 2

attached below

Part 3

C(t) = –0.30(t – 12)² + 40

F(t)=9/5C(t)+32

Substituting the values:

F(t)=9/5{–0.30 (t – 12)² + 40}+32

F(t) = -0.54 (t – 12)² + 72 + 32

F(t) = -0.54 (t – 12)² + 104

5, 6 and 7, should be simplish

good luck, i hope this helps :)

Step-by-step explanation:

3 0

2 years ago