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4 years ago

10

7a-5b+4 a=2, b=3 and c=-6

1 answer:

KengaRu [80]4 years ago

6 0

Answer: 3

Step-by-step explanation:

the statement given us:

7a-5b+4

a= 2

b= 3

so we have:

7*(2)-5*(3)+4

14-15+4 = 3

the answer is 3

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Hey can somebody help y+5=2(x+1)

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If you're looking for the equation, the answer is y=2x-3

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3 years ago

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Which of the following options have the same value as 2% of 90? Choose 2 answers: А 0.2.90 B 0.02.90 200.90 2.90 E 2 . 90 100

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Answer:

0.02.90 and 2.90

Step-by-step explanation:

2% of 90 equal to both 0.02.90 because are worth same.

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3 years ago

Brian rolls a number cube twice. What is the probability that the sum of the 2 rolls is less than 6 given that the first roll is

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If the first roll is a three, then the only chance of the sum of the two numbers being less than six is if you roll a 1 or a 2.
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4 years ago

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The hypotenuse of a right triangle has endpoints A(4, 1) and B(–1, –2). On a coordinate plane, line A B has points (4, 1) and (n

GarryVolchara [31]

Answer:

$(-1,1),(4,-2)$

Step-by-step explanation:

Given: The hypotenuse of a right triangle has endpoints A(4, 1) and B(–1, –2).

To find: coordinates of vertex of the right angle

Solution:

Let C be point $(x,y)$

Distance between points $(x_1,y_1),(x_2,y_2)$ is given by $\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

$AC=\sqrt{(x-4)^2+(y-1)^2}\\BC=\sqrt{(x+1)^2+(y+2)^2}\\AB=\sqrt{(4+1)^2+(1+2)^2}=\sqrt{25+9}=\sqrt{34}$

ΔABC is a right angled triangle, suing Pythagoras theorem (square of hypotenuse is equal to sum of squares of base and perpendicular)

$34=\left [ (x-4)^2+(y-1)^2 \right ]+\left [ (x+1)^2+(y+2)^2 \right ]$

Put $(x,y)=(-1,1)$

$34=\left [ (-1-4)^2+(1-1)^2 \right ]+\left [ (-1+1)^2+(1+2)^2 \right ]\\34=25+9\\34=34$

which is true. So, $(-1,1)$ can be a vertex

Put $(x,y)=(4,-2)$

$34=\left [ (4-4)^2+(-2-1)^2 \right ]+\left [ (4+1)^2+(-2+2)^2 \right ]\\34=9+25\\34=34$

which is true. So, $(4,-2)$ can be a vertex

Put $(x,y)=(1,1)$

$34=\left [ (1-4)^2+(1-1)^2 \right ]+\left [ (1+1)^2+(1+2)^2 \right ]\\34=9+4+9\\34=22$

which is not true. So, $(1,1)$ cannot be a vertex

Put $(x,y)=(2,-2)$

$34=\left [ (2-4)^2+(-2-1)^2 \right ]+\left [ (2+1)^2+(-2+2)^2 \right ]\\34=4+9+9\\34=22$

which is not true. So, $(2,-2)$ cannot be a vertex

Put $(x,y)=(4,-1)$

$34=\left [ (4-4)^2+(-1-1)^2 \right ]+\left [ (4+1)^2+(-1+2)^2 \right ]\\34=4+25+1\\34=30$

which is not true. So, $(4,-1)$ cannot be a vertex

Put $(x,y)=(-1,4)$

$34=\left [ (-1-4)^2+(4-1)^2 \right ]+\left [ (-1+1)^2+(4+2)^2 \right ]\\34=25+9+36\\34=70$

which is not true. So, $(-1,4)$ cannot be a vertex

So, possible points for the vertex are $(-1,1),(4,-2)$

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3 years ago

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three african elephants can weigh a total of 13,500 pounds. at this rate, how many do 2 african elephants weigh?

lidiya [134]

Answer:

Step-by-step explanation:

13500/3 = 4500

4500 x 2 = 9000

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3 years ago

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