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Setler79 [48]
3 years ago
11

Sisters Helen and Anne live 332 miles apart. For Thanksgiving, they met at their other sister's house partway between their home

s. Helen drove 3.2 hours and Anne drove 2.8 hours. Helen's average speed was 10 miles per hour faster than Anne's. Find Helen's average speed and Anne's average speed.
Mathematics
1 answer:
Blababa [14]3 years ago
8 0

Answer:

Helen: 60mph and Anne: 50mph

Step-by-step explanation:

3.2r+2.8(r-10)=332 is the equation that we use, given the information we have.

We distribute and combine like terms and add 28 to both sides and divide by 6.

3.2r+2.8(r-10)=332

3.2r+2.8r-28=332

                6r=360

             6r/6=360/6

                  r=60  So, Helen's speed is 60mph.

Next, we'll solve Anne's speed.

r-10=50

60-10=50  So, Anne's speed is 50mph.

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Trapezoid ABCD is shown on the graph. If the trapezoid is rotated 90 degrees
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Answer:

The coordinates of C" are (-7, 4)

Step-by-step explanation:

  • If the point (x, y) rotated about the origin by angle 90° counterclockwise, then its image is (-y, x)
  • If the point (x, y) translated horizontally to the left by h units, then its image is (x - h, y)

From the given figure

∵ ABCD is a trapezoid

∵ The coordinates of the ponit C are (4, 1)

∴ x = 4 and y = 1

∵ The trapezoid is rotated 90 degrees counterclockwise about the origin

→ By using the 1st rule above, change the sigh of y and switch them

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∴ C' = (-1, 4)

∵ The resulting image is translated 6 units left

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∴ C" = (x - h, y)

∵ h = 6

∵ x = -1 and y = 4

∴ C" = (-1 - 6, 4)

∴ C" = (-7, 4)

∴ The coordinates of C" are (-7, 4)

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