Answer:
84 is the highest possible course average
Step-by-step explanation:
Total number of examinations = 5
Average = sum of scores in each examination/total number of examinations
Let the score for the last examination be x.
Average = (66+78+94+83+x)/5 = y
5y = 321+x
x = 5y -321
If y = 6, x = 5×6 -321 =-291.the student cannot score -291
If y = 80, x = 5×80 -321 =79.he can still score higher
If If y = 84, x = 5×84 -321 =99.This would be the highest possible course average after the last examination.
If y= 100
The average cannot be 100 as student cannot score 179(maximum score is 100)
Answer:x>7 or x ≤ -3
Solving the 1st inequality
-6x +14 < -28 --------------- (Collect like terms)
-6x < -28 - 14
-6x < - 42 -------------------- (Divide both sides by -6)
Note: If you decide an inequality expression by a negative value, the inequality sign changes)
-6x/-6 > -42/-6
x > 7
Solving the 2nd inequality
9x + 15 ≤ −12 ----------- (Collect like terms)
9x ≤ −12 - 15
9x ≤ −27 ------------------(Divide both sides by 9)
9
9x/9 ≤ −27/9
x ≤ -3
Bring both results together, we get
x>7 or x ≤ -3
The final result is complex (i.e. can't be combined together).
Step-by-step explanation:
Answer:
tell him tell him dphones are trash and slow
Step-by-step explanation:
Answer:
t = 20 + q (minutes)
Step-by-step explanation:
The meeting consists of speaking and Question & Answer (Q&A) sessions.
Speaking session = 20 minutes
Q&A session = q minutes
Total number of minutes spent for the two sessions = 20 + q (minutes)
But total number of minutes meeting lasted = t minutes.
Therefore, t = 20 + q (because they both represent the total number of minutes the meeting lasted)
Answer:
Adding the exponents
Step-by-step explanation:
Multiplying exponential terms with the same base
To multiply exponents with same base , we use exponential property
When we multiply exponents with same base then we add the exponents
So, adding the exponents best explains to simplify the expression that has same base with exponents .
