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borishaifa [10]
3 years ago
5

Sketch the area under the standard normal curve over the indicated interval and find the specified area. (Round your answer to f

our decimal places.) The area to the right of z = 1.51 is
Mathematics
1 answer:
Angelina_Jolie [31]3 years ago
7 0

Answer:

P(z>1.51) =1-P(Z

And i fwe look into the normalstandar dtable we can find the desired probability:

P(z>1.51) =1-P(Z

And then the The area to the right of z = 1.51 is 0.0655

Step-by-step explanation:

For this case we want to find the following probability:

P(z>1.51)

And for this case we can use the normal standard distribution and the complement rule and we have this:

P(z>1.51) =1-P(Z

And i fwe look into the normalstandar dtable we can find the desired probability:

P(z>1.51) =1-P(Z

And then the The area to the right of z = 1.51 is 0.0655

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2 years ago
Circle T has diameters RP and QS. The measure of ∠RTQ is 12° less than the measure of ∠RTS.
Olenka [21]

The measure of Arc Q P is 96°. We also know that ∠QTP is central angle, then the measure of arc QP is 96°.

Step-by-step explanation:

<u>Step 1</u>

If QS is a circle diameter,

then m∠QTS=180°.

Let x be the measure of angle RTQ: ∠RTQ =x.

so, let ∠RTQ = x

<u />

<u>Step 2</u>

According to the question,

∠RTQ = ∠RTS - 12°

⇒ ∠RTS = x + 12°

∴ ∠QTS = ∠RTQ + ∠RTS

= x + x + 12° = 2x + 12° = 180°

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⇒ x = 84°

⇒ ∠RTQ = 84°

<u></u>

<u>Step 3</u>

Now,

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∴ ∠QTP = 84° + 12° = 96°

As ∠QTP is the central angle, hence the measure of arc QP is 96°

<u></u>

<u>Step 4</u>

The Measure of arc QP = 96°

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