<span>Susanne is 16 years old.</span>
b = Bob's age
s = Susanne's age
d = Dakota's age
Bob's age is 4 times greater than Susanne's age:
b = 4s
Dakota is three years younger than Susanne:
d = s - 3
The sum of Bob's, Susanne's, and Dakota's ages is 93:
b + s + d = 93
solve these equations:
b = 4s
d = s - 3
b + s + d = 93
and get:
b = 64 years
s = 16 years
(remember that s = Susanne)
d = 13 years
Answer:
1. In the multiplication of the imaginary parts, the student forgot to square of i. OR
2. The student has only multiplied the real parts and the imaginary parts.
Correct value
.
Step-by-step explanation:
The given expression is

A student multiplies (4+5i) (3-2i) incorrectly and obtains 12-10i.
Student's mistake can be either 1 or second:
1. In the multiplication of the imaginary parts, the student forgot to square of i.
2. The student has only multiplied the real parts and the imaginary parts.

Which is not correct. The correct steps are shown below.
Using distributive property, we get



![[\because i^2=-1]](https://tex.z-dn.net/?f=%5B%5Cbecause%20i%5E2%3D-1%5D)


Therefore, the correct value of
is
.
No, 0=0 has an infinite amount of solutions.
Four times the sum of n plus six
The rule would be : 3^x, where x starts at 0.
3^0 is 1,
3^1 is 3, because 3 one time is 3.
3^2 is 9, because 3x3 is 9.
3^3 is 27, because 3x3x3 is 27
Answer: 3^x