Answer: uuf, hard
Step-by-step explanation: SORRY, DON'T KNOW
The top right is the answer. The base should be square with lengths of 8 and the height is 10.
Answer:
Step-by-step explanation:
The x-value is 3. Coordinate pairs are labeled as (x, y). In this case, the 3 is in the x position.
The point is located in the 4th quadrant. Quadrant labels move counter-clockwise, from 1 to 4 as shown below. In Quadrant 4, the x-value will always be positive, and the y-value will always be negative. This point has a positive x-value and negative y-value, so it is in this quadrant.
So 6+3 is 9 right? So let's just say it's 9:37 with a 45 min ride. 60 minutes are in a hour. 60 - 37 = 23. We have 23 minutes left until 10:00. 45- 23 = 22. Therefore it'd be 10:22 p.m.
3.01 m/s
This is a simple projectile calculation. What we want is a vertical velocity such that the time the droplet spends going up and going back down to the surface exactly matches the time the droplet takes to travel horizontally 0.800 meters. The time the droplet spends in the air will is:
V*sqrt(3)/2 ; Vertical velocity.
(V*sqrt(3)/2)/9.8 ; Time until droplet reaches maximum height
(V*sqrt(3))/9.8 ; Double that time for droplet to fall back to the surface.
The droplet's horizontal velocity will be:
V/2.
So the total distance the droplet travels will be:
d = (V*sqrt(3))/9.8 * V/2
d = V^2*sqrt(3)/19.6
Let's substitute the desired distance and solve for V
d = V^2*sqrt(3)/19.6
0.8 = V^2*sqrt(3)/19.6
15.68 = V^2*sqrt(3)
15.68/sqrt(3) = V^2
15.68/1.732050808 = V^2
3.008795809 = V
So after rounding to 3 significant figures, the archerfish needs to spit the water at a velocity of 3.01 m/s
Let's verify that answer.
Vertical velocity: 3.01 * sin(60) = 3.01 * 0.866025404 = 2.606736465
Time of flight = 2.606736465 * 2 / 9.8 = 0.531987034 seconds.
Horizontal velocity: 3.01 * cos(60) = 3.01 * 0.5 =
