Answer:
D
Step-by-step explanation:
|2x-3|=2x-1
need to consider two cases
(1) 2x-3<0 --> x<3/2
-(2x-3)=2x-1
x=1, and this is <3/2 so that's a valid solution
(2) 2x-3>=0 --> x>=3/2
2x-3=2x-1
-3 = -1 so there no solution for x>=3/2
The single solution is x=-1
Answer:

Step-by-step explanation:
=> ![\sqrt[7]{m^3}](https://tex.z-dn.net/?f=%5Csqrt%5B7%5D%7Bm%5E3%7D)
![\sqrt[7]{}= ^\frac{1}{7}](https://tex.z-dn.net/?f=%5Csqrt%5B7%5D%7B%7D%3D%20%5E%5Cfrac%7B1%7D%7B7%7D)
=> 
=> 
Answer:
The point on the y-axis is (0,-3) and the point on the x-axis is (6,0)
Step-by-step explanation:
Start by plotting -3 on the y-axis
Then move up 1 and over 2 from there
Answer:
a) P=0.8
b) P=0.67
c) P=0.05
d) P=0.33
e) P=0.45
Step-by-step explanation:
a. What is the probability that the household has only a cell phone and has high-speed Internet?
This probability is stated in the question: "Suppose of U.S. households having only a cell phone, 80% have high-speed Internet", so the probability is P=0.8.

b. What is the probability that the household has only a cell phone or has high-speed Internet?
This probability is equal to the sum of the probability of having only a cell phone and the probability of having high-speed internet, less the probability of having both (to avoid counting this household twice).

c. What is the probability that the household has only a cell phone and does not have high-speed Internet?
This is equal to the probability of not having high-speed internet given that it has a cell phone (complementaty of the proability of Point (a)) multiplied by the probability of having a cell phone.

d. What is the probability that the household does not have just a cell phone and does not have high-speed Internet?
This probability is complementary of the one calculated in Point (c).

e. What is the probability that the household does not have just a cell phone and does have high-speed Internet?
This is equal to the probability of having high-speed internet less the probability it has both (cell phone and internet).
