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Ymorist [56]
4 years ago
7

HELP PLEASE THIS IS EASY as 2+2=?)))))))) help please

Mathematics
1 answer:
Svetlanka [38]4 years ago
8 0
Hello there!

y = 3x - 10
3x + 2y = 16

We wanna solve y = 3x - 10 for y

Let start by Substitute 3x - 10 for y in 3x + 2y = 16
But what does that even mean? It mean that we wanna replace y by 3x - 10.

3x + 2y = 16

3x + 2(3x - 10) = 16     Did you see what I did? I hope so!

3x + 6x - 20 = 16

9x - 20 = 16

Now add 20 on both sides

9x - 20 + 20 = 16 + 20

9x = 36

Then add 9 on both sides

9x/9 = 36/9

x = 4

Now we gonna use the value of x to find the value of y. We gonna do that by Substitute 4 for x in y = 3x - 10

y = 3x - 10

y = 3(4) - 10

y = 12 - 10

y = 2

Thus,

The solution is: x = 4 and y = 2

Type in order pair? Well, it should be like this:

(4,2)


I hope this helps. As always, it is my pleasure to help students like you!
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Rewrite the expression using exponents .Then find the product
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Answer:

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3 years ago
According to Reuters, a survey undertaken by the National Center for Health Statistics revealed that about 25% of U.S. household
ddd [48]

Answer:

a) P=0.8

b) P=0.67

c) P=0.05

d) P=0.33

e) P=0.45

Step-by-step explanation:

a. What is the probability that the household has only a cell phone and has high-speed Internet?

This probability is stated in the question: "Suppose of U.S. households having only a cell phone, 80% have high-speed Internet", so the probability is P=0.8.

P(C\&I)=0.8

b. What is the probability that the household has only a cell phone or has high-speed Internet?

This probability is equal to the sum of the probability of having only a cell phone and the probability of having high-speed internet, less the probability of having both (to avoid counting this household twice).

P(C\,orI\,)=P(C)+P(I)-P(C)*P(I|C)=0.25+0.65-(0.25*0.8)=0.25+0.62-0.20=0.67

c. What is the probability that the household has only a cell phone and does not have high-speed Internet?

This is equal to the probability of not having high-speed internet given that it has a cell phone (complementaty of the proability of Point (a)) multiplied by the probability of having a cell phone.

P(C\&\bar I)=P(\bar I|C)*P(C)=(1-P(\I|C))*P(C)=(1-0.8)*0.25 = 0.2*0.25 = 0.05

d. What is the probability that the household does not have just a cell phone and does not have high-speed Internet?

This probability is complementary of the one calculated in Point (c).

P(\bar C \,or\, \bar I)=1-P(C\, or\,I)=1-0.67=0.33

e. What is the probability that the household does not have just a cell phone and does have high-speed Internet?

This is equal to the probability of having high-speed internet less the probability it has both (cell phone and internet).

P(\bar C\&I)=P(I)-P(I|C)*P(C)=0.65-0.8*0.2=0.65-0.2=0.45

7 0
4 years ago
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