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N76 [4]
4 years ago
12

A 13 g rubber stopper is swung in a horizontal circle with a radius of 0.85 m with a period of 0.65 s. (a) How fast is the stopp

er moving? (b) What is the centripetal acceleration of the stopper? (c) Find the centripetal force that is exerted on the stopper.
Physics
1 answer:
NISA [10]4 years ago
8 0

Explanation:

(a) v = 2π r / t

v = 2π (0.85 m) / (0.65 s)

v = 8.2 m/s

(b) a = v² / r

a = (8.2 m/s)² / (0.85 m)

a = 79 m/s²

(c) F = ma

F = (0.013 kg) (79 m/s²)

F = 1.0 N

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