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g100num [7]
3 years ago
11

This multiple-concept example provides a review of the concepts that play roles here. An engine has an efficiency of 63% and pro

duces 5284 J of work. (a) Determine the input heat. (Give your answer to the nearest 10 J.)
Physics
1 answer:
frozen [14]3 years ago
4 0

Answer:

8387 J

Explanation:

work produced= 5284 J

efficiency of 63%

the efficiency η= Work done÷ heat supplied

\eta= \frac{W}{Q_s}

0.63= \frac{5284}{Q_s}

solving Q_s= 8397 J

therefore,  the input heat=  8387 J

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A car traveling with 500,000 J of kinetic energy is brought to a kinetic energy of
allsm [11]

Answer:

33,333.33 N

Explanation:

Given that :

Initial kinetic energy = 500,000 J

Final kinetic energy = 100,000 J

Using the relation :

Force * time = change in momentum (Newton's law)

Force (F) * 0.12 = (500,000 - 100,000)

0.12F = 400,000 J

Force = (400,000 J) / 0.12s

Force = 33333.333

Force = 33,333.33 N

3 0
3 years ago
Two long, straight wires are separated by 0.120 m. The wires carry currents of 11 A in opposite directions, as the drawing indic
rewona [7]

Answer:

The magnitude of the magnetic field is 1.83 x 10^{-5} T.

Explanation:

The flow of an electric current in a straight wire induces magnetic field around the wire. When current is flowing through two wires in the same direction, a force of attraction exists between the wires. But if the current flows in opposite directions, the force of repulsion is felt by the wires.

In the given question, the direction of flow of current through the wires is opposite, thus both wires applies the same field on each other. The result to repulsion between them.

The magnetic field (B) between the given wires can be determined by:

B = \frac{U_{o}I }{2\pi r}

where: I is the current, r is the distance between the wires and U_{0} is the magnetic field constant.

But, I = 11 A, r = 0.12 m and U_{0} = 4\pi x 10^{-7} Tm/A

So that;

B = \frac{4\pi *10^{-7}*11 }{2\pi *0.12}

   = 1.8333 x 10^{-5}

B = 1.83 x 10^{-5} T

6 0
3 years ago
A 2.0-kg ball is at rest when a horizontal force of 5.0 N is applied. In the absence of friction, what is the speed of the ball
Rzqust [24]

Answer:

v = 7.1 m/s

Explanation:

Work applied will change kinetic energy

Fd = ½mv²

v = √(2Fd/m) = √(2(5.0)(10) / 2.0) = √50 = 7.07... m/s

7 0
3 years ago
Sa fait combien 2×5÷6​
Triss [41]

Answer:

1.66666666667

Explanation:

divide the 5 and 6 first

8 0
3 years ago
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If two charged balloons are 24cm apart and they feel a force of electrical repulsion of 20N, what would the force of electrical
OverLord2011 [107]

Answer:

Soory

Explanation:

I really dont know but i will send you wait

5 0
3 years ago
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