Given that,
The radius of a circular path, r = 32 m
The time of one revolution of a rider is 0.98 s.
To find,
The speed of the rider.
Solution,
Let v is the speed of the rider. Speed is equal to total distance divided by time taken.

So, the speed of the rider is 205.16 m/s.
Answer: A. It can only be motionless.
Explanation: When balanced forces act on an object, the object will not move. The only way that object can move is if the forces become unbalanced. Suppose there is a shoe on a table. You are pulling back on the shoe with a force of 3 newtons. But the friction from the shoe rubbing on the table is also 3 newtons of force. But the gravity pulling down on the shoe is also 3 newtons. Nothing will move. The only way the shoe can move is if you pulled with a little more force. The shoe would then move because the force you are pulling with is greater than the other forces acting on the shoe.
Ex 2: You are playing tug of war. Team a is pulling with 20 Newtons of force. Team b is also pulling with 20 newtons of force. The rope does not move. Team a starts to pull a little harder. Now they are pulling with 25 Newtons of force. Now the rope starts moving their way.
Answer:
B) 4500 Pa
Explanation:
As pressure is force per unit area,
P = F/A
It stands to reason that the smallest pressure for a given force is when it is shared by the largest area.
The possible areas are
0.30(0.40) = 0.12 m²
0.30(0.50) = 0.15 m²
0.40(0.50) = 0.20 m²
The pressure when the face with the largest area (0.20 m²) is down is
P = 900 / 0.20 = 4500 N/m² or 4500 Pa
the other possible pressures would be
900/0.15 = 6000 Pa
900/0.12 = 7500 Pa
which are both larger than our solution.
Answer:
elastic partial width is 2.49 eV
Explanation:
given data
ER E = 250 eV
spin J = 0
cross-section magnitude σ = 1300 barns
peak P = 20ev
to find out
elastic partial width W
solution
we know here that
σ = λ²× W / ( E × π × P ) ...................1
put here all value
σ = (0.286)² × W ×
/ ( 250 × π × 20 )
1300 ×
= (0.286)² × W ×
/ ( 250 × π × 20 )
solve it and we get W
W = 249.56 ×
so elastic partial width is 2.49 eV