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sergejj [24]
3 years ago
13

A system does 1.80×10^{8}J of work while 7.50×10^{8}J of heat transfer occurs to the environment. What is the change in internal

energy of the system assuming no other changes (such as in temperature or by the addition of fuel)? (answer in ×10^{8}J)
Physics
1 answer:
LiRa [457]3 years ago
6 0

Answer:

ΔU = -9.30  x 10⁸ J

Explanation:

given,                                                

Work done of the system (W)= 1.8 x 10⁸ J

heat transfer to the environment (ΔQ)= 7.50 × 10⁸ J

Using first law of thermodynamics

ΔQ = ΔU + ΔW                                          

In the case heat is given to the system  so the heat transfer is negative.

-7.50 × 10⁸ = ΔU + 1.8 x 10⁸                

ΔU = -7.50 × 10⁸ - 1.8 x 10⁸              

ΔU = -9.30  x 10⁸ J                                  

Hence, the change in internal energy is equal to -9.30 x 10⁸ J

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A circular ride has a radius of 32 m If the time of one revolution of a rider is 0.98 s what is the speed of the rider?
11111nata11111 [884]

Given that,

The radius of a circular path, r = 32 m

The time of one revolution of a rider is 0.98 s.

To find,

The speed of the rider.

Solution,

Let v is the speed of the rider. Speed is equal to total distance divided by time taken.

v=\dfrac{2\pi r}{t}\\\\v=\dfrac{2\pi \times 32}{0.98}\\\\v=205.16\ m/s

So, the speed of the rider is 205.16 m/s.

6 0
3 years ago
When balanced forces act on an object, what type of motion can the object have?
Lesechka [4]

Answer: A. It can only be motionless.

Explanation: When balanced forces act on an object, the object will not move. The only way that object can move is if the forces become unbalanced. Suppose there is a shoe on a table. You are pulling back on the shoe with a force of 3 newtons. But the friction from the shoe rubbing on the table is also 3 newtons of force. But the gravity pulling down on the shoe is also 3 newtons. Nothing will move. The only way the shoe can move is if you pulled with a little more force. The shoe would then move because the force you are pulling with is greater than the other forces acting on the shoe.

Ex 2: You are playing tug of war. Team a is pulling with 20 Newtons of force. Team b is also pulling with 20 newtons of force. The rope does not move. Team a starts to pull a little harder. Now they are pulling with 25 Newtons of force. Now the rope starts moving their way.

8 0
3 years ago
4. O/N 15/P11/Q11
anygoal [31]

Answer:

B) 4500 Pa

Explanation:

As pressure is force per unit area,

P = F/A

It stands to reason that the smallest pressure for a given force is when it is shared by the largest area.

The possible areas are

0.30(0.40) = 0.12 m²

0.30(0.50) = 0.15 m²

0.40(0.50) = 0.20 m²

The pressure when the face with the largest area (0.20 m²) is down is

P = 900 / 0.20 = 4500 N/m² or 4500 Pa

the other possible pressures would be

900/0.15 = 6000 Pa

900/0.12 = 7500 Pa

which are both larger than our solution.

5 0
3 years ago
Neutrons incident on a heavy nucleus with spin J 0 show a resonance at an incident energy ER = 250 eV in the total cross-section
ivolga24 [154]

Answer:

elastic partial width is 2.49 eV

Explanation:

given data

ER  E = 250 eV

spin J = 0

cross-section magnitude σ = 1300 barns

peak P = 20ev

to find out

elastic partial width W

solution

we know here that

σ = λ²× W /  ( E × π × P )     ...................1

put here all value

σ = (0.286)² × W  × 10^{-16}/  ( 250 × π × 20 )

1300 × 10^{-24} = (0.286)² × W  × 10^{-16}/  ( 250 × π × 20 )

solve it and we get W

W = 249.56 × 10^{-2}

so elastic partial width is 2.49 eV

8 0
4 years ago
A boy is looking into a plane mirror .His nose is 30 cm in front of the mirror .How far is his nose from where its image appears
natima [27]

Answer:

60cm

Explanation:

30+30=60

8 0
3 years ago
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