Answer:
A) f(x) = 6x + 14
Step-by-step explanation:
6(1) + 14 = 20
6 + 14 = 20
6(1.5) + 14 = 23
9 + 14 = 23
6(2) + 14 = 26
12 + 14 = 26
and so on...
FACTOR ALL OF THE EQUATIONS INTO "y = (x-h)^2 + k," AND THE EQUATION'S VERTEX IS (h,k)
10. y = (x+2)^2 - 11 --> (-2, -11)
11. y = -(x-4)^2 + 32 --> (4, 32)
12. y = 3(x-1)^2 - 5 --> (1, -5)
13. y = -2(x+2)^2 + 5 --> (-2, 5)
14. y = 2(x+1)^2 - 1 --> (-1, -1)
15. y = -5(x-1)^2 + 8 --> (1, 8)
16. y = 3(x-3)^2 - 26 --> (3, -26)
17. y = (x+5)^2 - 32 --> (-5, -32)
18. y = -(x-3)^2 + 10 --> (3, -10)
Hi there!
Using compatible numbers it would be:
12 ÷ 2 = 6.
Now when you divide it, the answer would be close to 6.
So, 12 ÷ 2 = 6 would be using compatible numbers.
Hope this helps ;)
Answer:
304m^2
Step-by-step explanation:
First find the surface area of the base by multiplying the length by the width.
(12m) (8m)= 96m^2
Second, find the surface area of the front and back triangles using the formula <em>1/2 (base) (height)</em>. Use the length for the base.
1/2 (12m) (10m)= 60m^2
Next, find the surface area of the side triangles using the formula <em>1/2 (base) (height). </em>Use the width as the base.
1/2 (8m) (11m)= 44m^2
Last, add the surface area of each section. Make sure you add the area of each face.(we only solved for 1 of the front/ back triangles and 1 of the side triangles) To make it easier to understand I wrote out an equation to show how I added the surface areas.
base=a, front/ back triangles= b, side triangles=c
SA= a + 2b +2c or SA= a +b +b +c +c
Using one of the equations above solve for the total surface area.
SA= (96m^2) + (60m^2) +(60m^2) +(44m^2) +(44m^2)
or
SA= (96m^2) + 2(60m^2) +2(44m^2)
SA= (96m^2) +(120m^2) +(88m^2)
SA= 304m^2
The area of the red piece of paper is A= 4(2*4)= 4*8= 32 in^2.
The area of the blue piece of paper is A= 3*7=21 in^2. You subtract 21 from 32 and the difference is 11. So 11in^2 is visible.
