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4 years ago

You push a coin across a table. The coin stops how does the motion relate to the balance and unbalanced forces

Mathematics

2 answers:

Wewaii [24]4 years ago

6 0

When it is in motion the force is unbalanced. When it stops the forces are balanced.

Setler [38]4 years ago

3 0

Answer with explanation:

When you push a coin across a Table , the unbalanced force is that force which cause the change in motion of the object.

→Here force applied by my fingers is greater than frictional force acting on the table .That's why the coin is moving forward.So force applied by my fingers and Frictional force applied by the table on the coin are Unbalanced forces.

→When the coin stops no force acts on it , so at that point of time i am not applying any force on it due to which it is not moving just it is at rest.So that Position or at that duration force acting on the coin is Balanced.

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svet-max [94.6K]

Rearrange to: x^2 + 18x - 25 = 0
Then factorise (I like to do it by completing the square):
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3 years ago

What is the solution of the system?

Kryger [21]

Greetings!

Solve the System, using Elimination:
$\left \{ {{4x+2y=18} \atop {2x+3y=15}} \right.$

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$\left \{ {{4x+2y=18} \atop {4x+6y=30}} \right.$

Eliminate variable x:
$-\frac{ \left \{ {{4x+2y=18} \atop {4x+6y=30}} \right.}{0x-4y=-12}$

$4y=-12$

Divide both sides by 4:
$\frac{4y}{4}= \frac{12}{4}$

$y=3$

Input this value into one of the Equations:
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Simplify:
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$(4x+6)+(-6)=(18)+(-6)$

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Divide both sides by 4.
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I hope this helped!
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3 years ago

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dezoksy [38]

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3 years ago

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k0ka [10]

Answer:

x = $\frac{3}{2}$

Step-by-step explanation:

Given

f(x) = $\frac{x-4}{2x-3}$

The denominator cannot be zero as this would make f(x) undefined.

Equating the denominator to zero and solving gives the value that x cannot be and if the numerator is non zero for this value then it is a vertical asymptote.

2x - 3 = 0 ⇒ 2x = 3 ⇒ x = $\frac{3}{2}$

Thus x = $\frac{3}{2}$ is the vertical asymptote

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