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Mandarinka [93]
3 years ago
11

Kurt does chores in his neighborhood. The graph shows Kurt’s savings goal for the summer. If he washes 15 cars, how many lawns w

ill he have to mow to meet his goal? I need help for this thank u❤️

Mathematics
1 answer:
Dima020 [189]3 years ago
8 0
25. Because (30/50)/(2)= 15/25
15= cars washed
25 = lawns mowed
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Use the following information to answer the question that follows:
sveticcg [70]

Option E is correct. The amount Mayra deposited into the account quarterly is $1,146.35 where the value of n is 4

In order to get the amount compounded quarterly, we will use the compounded interest formula as shown:

A = P(1+r/n)^nt where:

A is the amount after 5 years = $6000

r is the rate (in %) = 6% = 0.06

n is the compounding time =  1/4 (quarterly)

t is the time taken (in years) = 5 years

Required

Amount invested quarterly.

First, we need to get the amount initially invested

Substitute the given values into the formula;

6000 = P(1+0.06(4))^{5/4)}

6000 = P(1+0.24)^1.25

6000 = P (1.24)^1.25

6000 = 1.3085P

P = 6000/1.3085

P = $4,585.40

The amount initially deposited will be $4,585.40

The amount deposited quarterly = P/n where n = 4

Amount deposited quarterly = $4,585.40/4

Amount deposited quarterly = $1,146.35

Therefore the amount Mayra deposited into the account quarterly is $1,146.35 where the value of n is 4.

Learn more here: brainly.com/question/18456266

5 0
3 years ago
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Ray is x years old. His brother ron is y years older than ray. What is the sum of their ages now?.
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Answer:

the answer is x( Ray) + y( Ron)

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What figure is described below?<br><br> the points in space equidistant from the endpoints of PQ.
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The question is slightly weird.

You have a piece of line, and its ends are 'P' and 'Q'.

All of the points on the paper that are the same distance
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segment-PQ and is perpendicular to it.
Other words:  The line that is perpendicular to PQ at its mid-point.
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All of the points in space that are the same distance from
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7 0
4 years ago
The length of bills backyard swimming pool is 60 feet longer than the width of the pool. The surface area of the water is 1600 s
shutvik [7]

Answer:

The width is 20 ft and the length is 80 ft

Step-by-step explanation:

Area = l * w

l = w +60

SA = 1600 ft^2 ( which is the regular area)  The surface area of the water is just what is on top  which is length times width

1600 = l*w

Substitute in l = w+60

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Distribute the w

1600 = w^2 +60w

Subtract 1600 from each side

1600-1600 = w^2 + 60w -1600

0 =  w^2 + 60w -1600

Factor

0=(w-20) (w+80)

Using the zero product property

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w=20  or w=-80

The width cannot be negative   so

w=20

Now we need to find the length

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2-x+3=16 is the answer. good luck?
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