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3 years ago

When you find the volume of a sphere, what are you finding out? explain

Mathematics

1 answer:

Aloiza [94]3 years ago

3 0

Volume of a sphere is all of the volume enclosed within the sphere.

4/3(pi)r^3

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Please help me on this, thank you

Mumz [18]

Answer:

the formula

Step-by-step explanation:

substitute the formula with the numbers give n-2 is number of sides -2 fyi

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3 years ago

If Maria drew her paintings on a 1 inch grid paper,how many squares would te painting cover?

lesya692 [45]

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3 years ago

15. What's the area of the room in this diagram? A. 25 square feet B. 166 square feet C. 156 square feet D. 84 square feet

Varvara68 [4.7K]

d is the answer' because it is :D

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3 years ago

Solve:<br> 1 - 2k += = -3k

MariettaO [177]

Answer:

-1

Step-by-step explanation:

1-2k=-3k

1-2k+2k=-3k+2k

1=-1k

1/-1=-1k/-1

-1=k

3 0

3 years ago

Read 2 more answers

The graph of f is given in the figure to the right. Let A(x)equals=Integral from 0 to x f left parenthesis t right parenthesis

Tpy6a [65]

Answer:

$A(4)=-4\pi$

$A(8)=-4\pi +8$

$A(12)=-4\pi +16$

$A(14)=-4\pi +15$

Step-by-step explanation:

we are given

$A(x)=\int\limits^x_0 f{x} \, dx$

Calculation of A(4):

we can plug x=4

$A(4)=\int\limits^4_0 f{x} \, dx$

Since, this curve is below x-axis

so, the value of integral must be negative

and it is quarter of circle

so, we can find area of quarter circle

radius =4

$A(4)=-\frac{1}{4}\times \pi \times (4)^2$

$A(4)=-4\pi$

Calculation of A(8):

we can plug x=8

$A(8)=\int\limits^8_0 f{x} \, dx$

we can break into two parts

$A(8)=\int\limits^4_0 f{x} \, dx+\int\limits^8_4 f{x} \, dx$

now, we can find area and then combine them

$A(8)=-4\pi +\frac{1}{2}\times 4\times 4$

$A(8)=-4\pi +8$

Calculation of A(12):

we can plug x=12

$A(12)=\int\limits^12_0 f{x} \, dx$

we can break into two parts

$A(12)=\int\limits^4_0 f{x} \, dx+\int\limits^8_4 f{x} \, dx+\int\limits^12_8 f{x} \, dx$

now, we can find area and then combine them

$A(12)=-4\pi +\frac{1}{2}\times 8\times 4$

$A(12)=-4\pi +16$

Calculation of A(14):

we can plug x=14

$A(14)=\int\limits^14_0 f{x} \, dx$

we can break into two parts

$A(14)=\int\limits^4_0 f{x} \, dx+\int\limits^8_4 f{x} \, dx+\int\limits^12_8 f{x} \, dx+\int\limits^14_12 f{x} \, dx$

now, we can find area and then combine them

$A(14)=-4\pi +\frac{1}{2}\times 8\times 4-\frac{1}{2}\times 1\times 2$

$A(14)=-4\pi +16-1$

$A(14)=-4\pi +15$

8 0

3 years ago