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3 years ago

Write 3 2/5 as an improper fraction.

Mathematics

2 answers:

Vlada [557]3 years ago

4 0

Answer:

17/5

Step-by-step explanation:

3 x 5

15+2

17/5

Serhud [2]3 years ago

4 0

Answer:

3 2/5 as am improper fraction would be 17/5

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Turkey tastes like napkins

vesna_86 [32]

So you ate napkins before? And some turkey is dry lol

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3 years ago

Explain how to find the product of the sum and difference of two terms. Give an example with your explanation.

hjlf

Given two terms a, b.
Sum of terms = a+b
Difference of terms = a-b
Product of sum and difference (do not forget parentheses)
=(a+b)(a-b)
which can be expanded as=a^2-b^2

We can make use of this property to calculate with lightning speed, assuming you know the squares of numbers.

For example,
8*6=(7+1)(7-1)=7^2-1^2=48
9*7=(8+1(8-1)=8^2-1^2=64-1=63
5*15 = (10+5)(10-5)=10^2-5^2=75
22*18=(20+2)(20-2)=20^2-2^2=400-4=396
63*57=(60+3)(60-3)=60^2-3^2=3600-9=3591
128*112=(120+8)(120-8)=120^2-8^2=14400-64=14336
We can go on and on!

8 0

3 years ago

a rectangle has side lengths (2x -5) meters and ( 2x + 6) meters. write a linear expression in simplest form to represent the pe

NikAS [45]

Answer:

perimeter=2(l+w)

2(2x+6 + 2x-5)

perimeter=2(2×12+6) +2×12-5)

2(30+19)

2(49)

p=98m

3 0

3 years ago

What is the area of ABC?

Salsk061 [2.6K]

Answer:

Area of triangle ABC = 10

Option C is correct.

Step-by-step explanation:

We need to find area of triangle ABC

We are given A(2,1) B(4,7) and C(6,3)

The formula used to find $Area \ of \ triangle=\frac{1}{2}base\times height$ ABC is:

In the given triangle base= AC and height = BC

First we need to find the distance between A and C and B and C

The formula used to find distance between AC $Distance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

We have $x_1=2, y_1=1, x_2=6, y_2=3$

Putting values and finding distance

$Distance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\\Distance=\sqrt{(6-2)^2+(3-1)^2}\\Distance=\sqrt{(4)^2+(2)^2}\\Distance=\sqrt{16+4}\\Distance=\sqrt{20}$

find distance between BC $Distance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

We have $x_1=4, y_1=7, x_2=6, y_2=3$

Putting values and finding distance

$Distance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\\Distance=\sqrt{(6-4)^2+(3-7)^2}\\Distance=\sqrt{(2)^2+(4)^2}\\Distance=\sqrt{4+16}\\Distance=\sqrt{20}$

So, We have height = $\sqrt{20}$ and base = $\sqrt{20}$

Finding area of triangle

$Area \ of \ triangle=\frac{1}{2}base\times height\\Area \ of \ triangle=\frac{1}{2}\sqrt{20} \times \sqrt{20} \\Area \ of \ triangle=\frac{1}{2}\times 20\\Area \ of \ triangle=10$

So, Area of triangle ABC = 10

Option C is correct.

7 0

3 years ago

What is the volume of a sphere with a radius of 34.2 m, rounded to the nearest tenth

Brums [2.3K]

167558.7 meters cube

8 0

3 years ago