Given: AB ∥ DC , m CB =62°, m∠DAB=104° Find: m∠DEA, m∠ADB
1 answer:
Answer:
m∠DEA = 62° and m∠ADB = 318°
Step-by-step explanation:
, - (Given)
m∠CB = 62° (Given)
we have;
m∠CB ≅ m∠DA (parallel lines congruent arc theorem)
m∠DA = 62° = m∠DEA
m∠DAB = 104° Given
Therefore, m∠AB = 104° - 62° = 42° (sum of angle)
m∠DC = 360 - 62 - 62 - 42 = 194° (sum of angles around a circle)
m∠ADB = 360° - m∠AB (sum of angles around a circle)
Therefore, m∠ADB = 360° - 42° = 318°
The required angles are;
m∠DEA = 62° and m∠ADB = 318°
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