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QveST [7]
3 years ago
14

Can someone please help me

Mathematics
1 answer:
Aneli [31]3 years ago
5 0

Answer:

r = 5

Step-by-step explanation:

To solve for r, plug in the change in x values and change in y values, since the hypotenuse is simply the diagonal of both the y-coordinate and x-coordinates shown via drawing legs on the vertical and horizontal axis. So, since (0,0) is the initial point, r = sqr[(-4-0)^2 + (-3-0)^2 = sqr(16 + 9) = 5.

Now, the angle theta is the angle in which the sine, cosine, and tangent ratios are found. Simply use opposite over hypotenuse for sine, adjacent over hypotenuse for cosine, and opposite over adjacent for tangent using theta as the angle in which these values are obtained.

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y=mx+b, so now we must use two points to solve for the slope, or "m".

m=(y2-y1)/(x2-x1)

m=(0-15)/(5-0)

m=-15/5

m=-3  so our line so far is:

y=-3x+b, b=y-intercept=value of y when x=0, which we can see is 15 ft so:

y=-3x+15

Now the radius is x, so we must solve for x from the equation above...

-3x+15=y  subtract 15 from both sides

-3x=y-15  divide both sides by -3

x=(15-y)/3

And area of this circle is:

A=πx^2, and using x found above:

A=(π/9)(15-y)^2

A=(π/9)(225-30y+y^2), so when y=6 ft

A=(π/9)(225-30*6+6^2)

A=(π/9)(81)

A=9π or if we let π=pi

A=9pi ft^2
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Answer:

D

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