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3 years ago

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There was a 6 square foot piece of wrapping paper for a birthday present. It takes 3 3/8 feet of square feet of the paper to wra

p the present. How many pieces of 6 sqare foot paper are needed to wrap 3 of these presents

1 answer:

Citrus2011 [14]3 years ago

3 0

Answer: However, in real life it depends on the shape of the actual presents. If two sheets are used for the 2 presents. There should be enough left from those sheets to use for the third present. (They should be taped together.)

Step-by-step explanation: 6/3 then 3 over 8 ––> 3/8

6/ 27/8

= 6/1 / divide 27/8

= 6^2 /1 x 8/27 ^9 (^) –––> this mean square root of 2 or 9

6 cancels and 27 cancel

= 16/9

=1 7/9

However you will still need to buy 2 sheets

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How to evaluate the limit

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3 years ago

Principle = 30,000<br>Time = 4 years<br>Rate = 30<br>Then find the simple interest ?

Nutka1998 [239]

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$\begin{gathered}{\Large{\textsf{\textbf{\underline{\underline\color{brown}{Given:}}}}}}\end{gathered}$

${\dashrightarrow \sf{Principle = Rs.30000}}$
${\dashrightarrow \sf {Time = 4 \: years}}$
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$\begin{gathered}\end{gathered}$

$\begin{gathered}{\Large{\textsf{\textbf{\underline{\underline\color{brown}{To Find:}}}}}}\end{gathered}$

$\dashrightarrow{\sf{Simple \: Interest }}$

$\begin{gathered}\end{gathered}$

$\begin{gathered}{\Large{\textsf{\textbf{\underline{\underline\color{brown}{Using Formula:}}}}}}\end{gathered}$

$\dag{\underline{\boxed{\sf{ S.I = \dfrac{P \times R \times T}{100}}}}}$

Where

$\dashrightarrow{\sf{S.I = Simple \: Interest }}$
${\dashrightarrow{\sf{P = Principle }}}$
${\dashrightarrow{\sf{ R = Rate }}}$
${\dashrightarrow{\sf{T = Time}}}$

$\begin{gathered}\end{gathered}$

$\begin{gathered}{\Large{\textsf{\textbf{\underline{\underline\color{brown}{Solution:}}}}}}\end{gathered}$

${\quad {: \implies{\sf{ S.I = \bf{\dfrac{P \times R \times T}{100}}}}}}$

Substituting the values

${\quad {: \implies{\sf{ S.I = \bf{\dfrac{30000 \times 30\times 4}{100}}}}}}$

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${\quad {: \implies{\sf{ S.I = \bf{Rs.36000}}}}}$

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