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Sedaia [141]
3 years ago
13

You can upgrade lighting at your factory to LED bulbs that costs $6.95 each and last an average of 5 years. It costs $3.00 in la

bor to change a bulb. Over a 10-year period, about how much will it cost per year to install LED bulbs in 100 lamps and change the bulbs when they burn out?
A. $140
B $200
C $440
D $700
E $1,000
Mathematics
2 answers:
Maru [420]3 years ago
8 0

Answer:

$200

Step-by-step explanation:


kompoz [17]3 years ago
6 0
Labor is $3 per bulb, there is 100 lamps, so the labor cost would be 100 x 3 = $300.

The cost of one bulb is 6.95, the total cost of bulbs is 100 x 6.95 = $695

The total fr bulbs and labor is $695 + $300 = $995

The bulbs last 5 years so, for a 10 year period you would need to change the bulbs twice so total cost for 10 years would be 995 x 2 = $1990.

To find the cost per year, divide the total cost by the number of years:
1990 / 10 = 199 per year. Round to $200 per year.
 The answer is B.




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The volume of a shipping container is 448.656 cubic inches, and it can hold 24 smaller boxes. What's the volume of each of the s
madreJ [45]

Answer:

The volume of each of the smaller boxes = 18.694  inches³

Step-by-step explanation:

The volume of Shipping container = 448.656  inches³

The shipping container hold small boxes of numbers = 24

So, The volume of each of small boxes = \frac{448.656}{24} inches³

Or, The volume of each of small boxes = 18.694  inches³

Hence The volume of each of 24 small containers is 18.694 inches³ Answer

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4 years ago
What is 2,168.433 rounded to the nearest mile?
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Answer:

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8 0
3 years ago
Read 2 more answers
The one-time fling! Have you ever purchased an article of clothing (dress, sports jacket, etc.), worn the item once to a party,
Mama L [17]

Answer:

(a)\ P(x = 0) = 0.2725

(b)\ P(x \ge 1) =0.7275

(c)\ P(x \le 2) = 0.8948

Step-by-step explanation:

Given

n = 8 --- 8 friends

p = 15\% --- proportion that one-time fling

This question is an illustration of binomial probability, and it is represented as:

P(X = x) = ^nC_x* p^x * (1 - p)^{n-x}

Solving (a): P(x = 0) --- None has done one time fling

P(x = 0) = ^8C_0* (15\%)^0 * (1 - 15\%)^{8-0}

P(x = 0) = 1* 1 * (1 - 0.15)^{8}

P(x = 0) = 0.85^8

P(x = 0) = 0.2725

Solving (b): P(x \ge 1)

To do this, we make use of compliment rule:

P(x = 0) + P(x \ge 1) =1

Rewrite as:

P(x \ge 1) =1 - P(x = 0)

P(x \ge 1) =1 - 0.2725

P(x \ge 1) =0.7275

Solving (c): P(x\le 2)--- Not more than 2 has one time fling

This is calculated as:

P(x\le 2) = P(x = 0) + P(x =1) + P(x = 2)

We have:

P(x = 0) = 0.2725

P(x = 1) = ^8C_1* (15\%)^1 * (1 - 15\%)^{8-1}

P(x = 1) = 8* (0.15) * (1 - 0.15)^7

P(x = 1) = 0.3847

P(x = 2) = ^8C_2* (15\%)^2 * (1 - 15\%)^{8-2}

P(x = 2) = 28* (0.15)^2 * (1-0.15)^6

P(x = 2) = 0.2376

So:

P(x\le 2) = P(x = 0) + P(x =1) + P(x = 2)

P(x \le 2) = 0.2725 + 0.3847 + 0.2376

P(x \le 2) = 0.8948

4 0
3 years ago
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GrogVix [38]

Answer:

64

Step-by-step explanation:

4 cups * 16 quarts = 64 cups

6 0
3 years ago
Read 2 more answers
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Butoxors [25]

Answer:

y-intercept: (0, -3)

x-intercept: (5, 0)

Step-by-step explanation:

Trick question! The problem gives you the x and y intercepts. x intercept is when y is 0, and y intercept is when x = 0!

3 0
3 years ago
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