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Sedaia [141]
3 years ago
13

You can upgrade lighting at your factory to LED bulbs that costs $6.95 each and last an average of 5 years. It costs $3.00 in la

bor to change a bulb. Over a 10-year period, about how much will it cost per year to install LED bulbs in 100 lamps and change the bulbs when they burn out?
A. $140
B $200
C $440
D $700
E $1,000
Mathematics
2 answers:
Maru [420]3 years ago
8 0

Answer:

$200

Step-by-step explanation:


kompoz [17]3 years ago
6 0
Labor is $3 per bulb, there is 100 lamps, so the labor cost would be 100 x 3 = $300.

The cost of one bulb is 6.95, the total cost of bulbs is 100 x 6.95 = $695

The total fr bulbs and labor is $695 + $300 = $995

The bulbs last 5 years so, for a 10 year period you would need to change the bulbs twice so total cost for 10 years would be 995 x 2 = $1990.

To find the cost per year, divide the total cost by the number of years:
1990 / 10 = 199 per year. Round to $200 per year.
 The answer is B.




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If the equation looks like this: y = 2x +6 it is in what form?
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Answer:

B

Step-by-step explanation:

4 0
3 years ago
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Solve the system of inequalities<br> 1-12y&lt;:3y+1; 2-6y&gt;4+4y
ICE Princess25 [194]

For 1 - 12y < 3y+1;        y > 15

For 2 - 6y  >  4  +  4y;   y  <  -0.2

The given inequalities are:

1  -  12y < 3y  +  1

2 - 6y  >  4  +  4y

For 1  -  12y < 3y  +  1:

1  -  12y < 3y  +  1

Collect like terms

-12y  -  3y  <  1  -  1

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Multiply both sides by -1

-1(-15y)   >  0(-y)

15y    >   0

Divide both sides by 15

y   >  0/15

y   >   15

For 2 - 6y  >  4  +  4y

Collect like terms

-6y  - 4y  >  4  -  2

-10y   >   2

Multiply both sides by -1

-1(-10y)   <  2(-1)

10y   <  -2

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Learn more here: brainly.com/question/11316045

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3 years ago
Plz help!!!!!!!!!
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Answer:

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Step-by-step explanation:

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