Answer:
Therefore 200.96 ft.of fencing are needed to go around the pool path.
Step-by-step explanation:
Given, a circular swimming pool has a radius of 28ft. There is a path all the way around the pool. The width of the path 4 ft.
The radius of the outside edge the pool path is
= Radius of the pool + The width of the path
= (28+4) ft
= 32 ft.
To find the length of fencing, we need to find the circumference of outside the pool path.
Here r= 32 ft
The circumference of outside edge of the pool path
=
=200.96 ft.
Therefore 200.96 ft.of fencing are needed to go around the pool path.
Using translation concepts, it is found that the equation that represents the graph of g(x) is:
![g(x) = \sqrt[3]{x + 2}](https://tex.z-dn.net/?f=g%28x%29%20%3D%20%5Csqrt%5B3%5D%7Bx%20%2B%202%7D)
.
<h3>What is a translation?</h3>
A translation is represented by a change in the function graph, according to operations such as multiplication or sum/subtraction in it's definition.
In this problem, we have that g(x) is a shift left of 2 units of f(x), hence:
More can be learned about translation concepts at brainly.com/question/4521517
#SPJ1
There is no solutions.
6 ( y + 8 ) = 3 ( 2y - 7 )
6y + 48 = 6y - 21
-48 -48
6y = 6y - 27
+27 +27
33y÷33 = 6y÷33
y=2/11 or 0.18
Hope this helps!
Given :
∆GHI is an isosceles triangle with a vertex angle H.
m∠H=80°
To Find :
The m∠I.
Solution :
Since, H is the vertex angle.
So, m∠I = m∠G = x
We know, by angle sum property of triangle :
m∠I + m∠G + m∠H = 180°
2x + 80° = 180°
x = 50°
Therefore, m∠I = 50° .
