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IRISSAK [1]
4 years ago
15

Find the length of one side of a regular hexagon whose perimeter is 75 feet

Mathematics
1 answer:
Nikitich [7]4 years ago
8 0
Your answer should turn out to be C.:angle 2 and angle 5. :D
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I need help me need to match i am getting confuse.
gregori [183]

Answer:

1 A= pi 21^2

2 C=pi 21

3 A= pi 10.5^2

4 C= 2pi 10.5

Step-by-step explanation:

7 0
3 years ago
A steel oil tank is a cylinder with a diameter of 12 ft and a height of 18 ft. How many square feet of steel were needed to make
k0ka [10]

Answer:

it needed 30 square feet of stell

Step-by-step explanation:

6 0
3 years ago
The Box-and-Whisker Plot shown displays the number of daily text messages sent to a television channel regarding a political iss
lisabon 2012 [21]
D.99
that is the highest number you are putting on the thing
8 0
3 years ago
The blood cholesterol levels of men aged 55 to 64 are approximately normally distributed with mean 222 mg/dl and standard deviat
tatiyna

Answer:

It is provided that 10% of the men aged 55 to 64 have cholesterol level <u>270 mg/dl</u> or higher.

Step-by-step explanation:

Let <em>X</em> = blood cholesterol levels of men aged 55 to 64 years.

The random variable <em>X</em> follows a Normal distribution with mean <em>μ</em> = 222 mg/dl and standard deviation <em>σ</em> = 37 mg/dl.

It is provided that 10% of the men aged 55 to 64 have cholesterol level <em>x</em> mg/dl or higher.

Compute the value of <em>x</em> as follows:

P(X\geq x)=0.10\\P(\frac{X-\mu}{\sigma}\geq \frac{x-222}{37})=0.10\\P(Z\geq z)=0.10\\1-P(Z

Use the <em>z</em>-table to compute the value <em>z</em> for the probability 0.90.

The value of <em>z</em> is 1.29.

Compute the value of <em>x</em> as follows:

z=\frac{x-\mu}{\sigma}\\1.29=\frac{x-222}{37} \\x=222+(1.29\times37)\\=269.73\approx270

Thus, 10% of the men aged 55 to 64 have cholesterol level 270 mg/dl or higher.

3 0
3 years ago
How do you simplify 10 square root 96
cupoosta [38]
10 * √96

10 * √(16 * 6)

10 * √16 * √6

10 * 4 * √6

40 * √6

40√6
5 0
4 years ago
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