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erastovalidia [21]
4 years ago
7

Light bulbs of a certain type are advertised as having an averagelifetime of 750 hours. The price of these bulbs is very favorab

le,so a potential customer has decided to go ahead with a purchasearrangement unless it can be conclusively demonstrated thatthe true average lifetime is smaller than what is advertised. Arandom sample of 50 bulbs was selected, the lifetime of each bulbdetermined, and the appropriate hypothesis were tested usingMINITAB, resulting in the accompanying output.Variable N Mean St Dev SEMean ZP -Valuelifetime 50 738.44 38.20 5.40-2.14 0.016 What conclusion would be appropriate for a significance level of.05 ? .A significance level of .01 ?. What significance level wouldyou recommend ?
Mathematics
1 answer:
PilotLPTM [1.2K]4 years ago
7 0

answer 40

Step-by-step explanation:

because you added all together to make one

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What are the solutions to 2(x-7)^2 = 32?
MariettaO [177]
2(x-7)^2 = 32\\
(x-7)^2=16\\
x-7=-4 \vee x-7=4\\
x=3 \vee x=11

3 0
3 years ago
ryan rides his bicycle 5 miles in 3/4 hour. how many miles can he ride at the same rate in 1 hour? (in fractions)​
stepladder [879]

Answer:

20/3

Step-by-step explanation:

If Ryan rides his bike 5 miles in 3/4 of an hour, then he rides 5/3 miles in 1/4 of a hour (divide both by 3). To get to a full hour from 1/4, you need to multiply it by 4. You must do the same for 5/3. 5/3*4 is equal to 20/3.

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3 years ago
A digital gaming service offers a subscription plan with a $25 membership fee and charges a $2.50 per game rental fee. How many
erastova [34]

Answer:

They can get at most 10 games

The inequality is g=25+2.50x

Step-by-step explanation:

50=25+2.5x

50-25=25

25=2.5x

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6 0
3 years ago
Evaluate 27x1/3^3<br> I need it in simple form
ruslelena [56]

Step-by-step explanation:

27 \times  \frac{1}{ {3}^{3} }

= 27 \times  \frac{1}{27}

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7 0
2 years ago
Read 2 more answers
Find the critical value of x2 based on the given information H1 &gt;3.5 n=14 a=0.05
egoroff_w [7]

Answer:

The degrees of freedom are given by:

df = n-1=14-1=13

The significance level is \alpha=0.05 and then the critical value can be founded in th chi square table we need a quantile that accumulates 0.05 of the area in the right tail of the distribution and for this case is:

\chi^2_{\alpha}= 22.362

And if the chi square statistic is higher than the critical value we can reject the null hypothesis in favor of the alternative.

Step-by-step explanation:

We have the followign system of hypothesis:

Null hypothesis: \sigma^2 \leq 3.5

Alternative hypothesis: \sigma^2 >3.5

The degrees of freedom are given by:

df = n-1=14-1=13

The significance level is \alpha=0.05 and then the critical value can be founded in th chi square table we need a quantile that accumulates 0.05 of the area in the right tail of the distribution and for this case is:

\chi^2_{\alpha}= 22.362

And if the chi square statistic is higher than the critical value we can reject the null hypothesis in favor of the alternative.

4 0
3 years ago
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