3,500 (.024) = 84
84 (5) = $420 in simple interest
The negative exponents that are in the numerator pass to positive if the base is moved to the denominator, and the negative exponents that are in the denominator pass to positive if the base is moved to the numerator.
The the answer is the option B: xx^4 / y^2 y^6
The answer is yes. I think that I’m right
Answer:
Step-by-step explanation:
I always like to use the mean if I can. In this data set, it's probably not a very good idea. Too much weight is given to that 7.2 and the two 3.2s.
I would choose the median, because the mode is the same answer and that's a good enough reason for choosing anything. 2 out 3 isn't bad as they say in Baseball.
Answer:
0.477 is the probability that the average score of the 36 golfers was between 70 and 71.
Step-by-step explanation:
We are given the following information in the question:
Mean, μ = 70
Standard Deviation, σ = 3
Sample size, n = 36
Let the average score of all pro golfers follow a normal distribution.
Formula:
P(score of the 36 golfers was between 70 and 71)



0.477 is the probability that the average score of the 36 golfers was between 70 and 71.