The slope is rise/run
3 up and 3 to the left: 3/3 = 1
The slope is 1
Assuming graph is 1 units per box and y intercept is (0,y), looking at the graph you can see it’s (0,-1)
The y intercept is (0,-1)
53x12=636 that is your answer that is the way to estimate it your answer is 636 that is how many students can be seated
Answer:
Null hypothesis is: U1 - U2 ≤ 0
Alternative hypothesis is U1 - U2 > 0
Step-by-step explanation:
The question involves a comparison of the two types of training given to the salespeople. The requirement is to set up the hypothesis that type A training leads to higher mean weakly sales compared to type B training.
Let U1 = mean sales by type A trainees
Let U2 = mean sales by type B trainees
Therefore, the null hypothesis (H0) is: U1 - U2 ≤ 0
This implies that type A training does not result in higher mean weekly sales than type B training.
The alternative hypothesis (H1) is: U1 - U2 > 0
This implies that type A training indeed results in higher mean weekly sales than type B training.
Answer: D
Step-by-step explanation:
Consider the first equation. Subtract 3x from both sides.
y−3x=−2
Consider the second equation. Subtract x from both sides.
y−2−x=0
Add 2 to both sides. Anything plus zero gives itself.
y−x=2
To solve a pair of equations using substitution, first solve one of the equations for one of the variables. Then substitute the result for that variable in the other equation.
y−3x=−2,y−x=2
Choose one of the equations and solve it for y by isolating y on the left hand side of the equal sign.
y−3x=−2
Add 3x to both sides of the equation.
y=3x−2
Substitute 3x−2 for y in the other equation, y−x=2.
3x−2−x=2
Add 3x to −x.
2x−2=2
Add 2 to both sides of the equation.
2x=4
Divide both sides by 2.
x=2
Substitute 2 for x in y=3x−2. Because the resulting equation contains only one variable, you can solve for y directly.
y=3×2−2
Multiply 3 times 2.
y=6−2
Add −2 to 6.
y=4
The system is now solved.
y=4,x=2
