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Nata [24]
2 years ago
8

14. AMKL is an isosceles triangle with MK ML.If MK = 7x - 15, KL = 4x - 6, and ML = 10X - 12, find x and the measure of each sid

e.​
Mathematics
1 answer:
Alenkinab [10]2 years ago
8 0

Answer:

You can do it! Sorry i can't help because your on a different level. Try your best!

Step-by-step explanation:

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Sarah used 2.5 cups of cheese in a dish that serves 10 people. Amy used 1.6 cups of cheese in a dish that serves 8 people. Who h
motikmotik

Answer:

Amy

Step-by-step explanation:

Find their amounts of cheese per serving by dividing the cups of cheese by the number of people:

Sarah:

2.5/10

= 0.25

Amy:

1.6/8

= 0.8

Since 0.8 is bigger than 0.25, Amy has more cheese per serving.

8 0
3 years ago
Read 2 more answers
Numa P.A de razão 6, o primeiro termo é 2. Qual a posição do termo igual a 34? ( Me ajudem pfvr é pra hoje )
EastWind [94]
Será que hasta responden en este idioma x que yo no se
8 0
3 years ago
At the snack bar, hot dogs cost $4 each and bottled water costs $2 each. In the first business hour of the day, less than $12 wo
mart [117]

Answer:

(2, 2)

Step-by-step explanation:

just say it was mental math

7 0
2 years ago
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Can someone please help me I’m stuck I don’t know
Leviafan [203]

Answer:

140

Step-by-step explanation:

Because the lines are parallel:

\dfrac{DE}{35}=\dfrac{60}{15} \\\\DE=4\cdot 35=140

Hope this helps!

4 0
3 years ago
How are percent transmittance and absorbance related algebraically?
statuscvo [17]

Answer:

So, if all the light passes through a solution without any absorption, then absorbance is zero, and percent transmittance is 100%. If all the light is absorbed, then percent transmittance is zero, and absorption is infinite.

Absorbance is the inverse of transmittance so,

A = 1/T

Beer's law (sometimes called the Beer-Lambert law) states that the absorbance is proportional to the path length, b, through the sample and the concentration of the absorbing species, c:  


A ∝ b · c

As Transmittance, T =\dfrac{P}{P_0}

% Transmittance, \%T=100\times T

Absorbance,

A=\log_{10} \dfrac{P_0}{P}\\\\A =\log_{10}\times \dfrac{1}{T}\\\\A=\dfrac{\log_{10} 100}{\%T}\\\\A=(2 - log_{10})\times \%T

Hence, A=\log_{10}\times \dfrac{1}{T} is the algebraic relation between absorbance and transmittance.


8 0
2 years ago
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