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NikAS [45]
3 years ago
15

The area of a rectangle is 265.5 m2. If the length is 18 m, what is the perimeter of the rectangle?

Mathematics
1 answer:
julia-pushkina [17]3 years ago
4 0

Answer:

65.5 m

Step-by-step explanation:

Step 1. Find the width of the rectangle.

The formula for the area of a rectangle is

A = lw

Data:

A = 265.5 m²

l =     18    m

Calculation:

265.5 = 18w

w = 265.5/18 = 14.75 m

Step 2. Calculate the perimeter

The perimeter (P) of a rectangle is the sum of the lengths of its sides.

P = 2(l + w) = 2(18 + 14.75) = 2 × 32.75 = 65.5 m

The perimeter of the rectangle is 65.5 m.

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Segment YZ has endpoints (6, 3) and (3, 9). Find the coordinates of the point that divides the line segment directed from Y to Z
fenix001 [56]

Answer:

  (4, 7)

Step-by-step explanation:

The point of interest is ...

  P = (2Z +1Y)/(2+1) = ((2·3+6)/3, (2·9+3)/3)

  P = (4, 7)

__

The point that divides the segment into the ratio a:b is the weighted average of the endpoints, with the weights being "b" and "a". The weight of the first end point corresponds to the length of the far end of the segment.

8 0
3 years ago
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Can someone answer this question please please help me I really need it if it’s correct I will mark you brainliest .
lesya692 [45]

Formula for the area of a quarter circle: A = (pi x r^2) / 4

A = (pi x 1^2) / 4

A = 1pi / 4

A = 0.79 square centimeters

Hope this helps! :)

8 0
3 years ago
(x+7)^2+9=0<br><br> Find x with quadratics
Ne4ueva [31]

Answer:

x = -7 ±3i

Step-by-step explanation:

(x+7)^2+9=0

Subtract 9 from each side

(x+7)^2+9-9=0-9

(x+7)^2=-9

Take the square root of each side

sqrt((x+7)^2) = ±sqrt(-9)

We know sqrt(ab) = sqrt(a) sqrt(b)

x+7 = ±sqrt(-1) sqrt(9)

We know that sqrt(-1) is the imaginary number i

x+7 = ±i *3

x+7 =±3i

Subtract 7 from each side

x+7-7 = -7 ±3i

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6 0
3 years ago
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The sum of 5 times a larger number and twice a smaller is 5. The difference of 4 times the larger and the smaller number is 4. F
Gemiola [76]

Answer:

1 and 0

Step-by-step explanation:

Let's call the smaller number x and the larger number y.

This means 5y+2x=5.

Also, 4y-x=4.

This is a system of equations. There are two main ways two solve this.

Method 1: Substitution

5y+2x=5

4y-x=4

Solve for one of the variables, then substitute it back into one of the equations to solve for the other variable.

I will take 4y-x=4 and solve for x.

4y=4+x

x=4y-4

Then substitute for x in the other equation and solve for y.

5y+2x=5

5y+2(4y-4)=5

5y+8y-8=5

13y=13

y=1

Now we can go back to our equation for x and substitute for y.

x=4y-4

x=4(1)-4=0

y, the larger number, is 1 and

x, the smaller number, is 0

Method 2: Elimination

5y+2x=5

4y-x=4

Change the equations so that the coefficient of one of the variables in an equation is opposite the one in the other equation. Then add the equations and solve for each variable.

If I multiply both sides of the second equation, 4y-x=4, by 2, the coefficient of x will become -2. In the first equation, the coefficient is 2, so they will become opposites.

4y-x=4

becomes

8y-2x=8

Now we have 5y+2x=5 and 8y-2x=8.

Add the sides of both equations to cancel the x values.

5y+2x+8y-2x=5+8

13y=13

y=1

like last time, we can substitute for y in any of the original equations to get x.

5y+2x=5

5(1)+2x=5

5+2x=5

2x=0

x=0

y, the larger number, is 1 and

x, the smaller number, is 0

6 0
3 years ago
I will mark as brilliant please help
vodomira [7]
It’s C. x_< -2 Good luck
8 0
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