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kari74 [83]
3 years ago
13

What are the four next multiples of one over ten

Mathematics
2 answers:
Gennadij [26K]3 years ago
7 0
It would be
1/10
2/10
3/10
4/10
5/10
sergij07 [2.7K]3 years ago
4 0

1/10- 2/10- 3/10- 4/10- 5/10


Hope this helps!

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WdkNEIOEWHDEIWDHWWD/
KiRa [710]

Answer:

ok brainliest pls

Step-by-step explanation:

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3 years ago
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What's the nearest tenth of 1.91
Andre45 [30]
1.91 to the nearest tenth is 1.9
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"During their first swim through a water maze, 15 laboratory rats made the following number of errors (went the wrong way): 2, 1
velikii [3]

Answer:

mean = 7.8, median =5, and mode(s) =5

the shape of the distribution is positive skewed

Step-by-step explanation:

Find the mean, median and mode(s) for

2, 17, 5, 3, 28, 7, 5, 8, 5, 6, 2, 12, 10, 4, 3

the mean = sum of (2, 17, 5, 3, 28, 7, 5, 8, 5, 6, 2, 12, 10, 4, 3)/15 =

              =  7.8          

the median = 2, 2, 3, 3, 4, 5, 5, 5,  6, 7,  8, 10, 12, 17, 28, = the middle value, the 8th value falls in the middle = 5

the mode is the most occurring value = 5

2. Without constructing a frequency distribution or graph, would you characterize the shape of this distribution as balanced, positively skewed, or negatively skewed?

positive skewed or Right skewed because the value of the mean is greater than the median

A right skewed histogram is a positive skewed histogram (which means the tail is longer the positive direction) that have its tail to the right.For a right skewed histogram the mean has a larger value that the median because the peak of the skewness fall in the median range then the mean follow to the right. and the data drive the mean value to the right which increase in value.

Read more on Brainly.com - brainly.com/question/14703862#readmore

5 0
3 years ago
I need to find the area of the shaded ara
notsponge [240]
Area of shaded area= area of large rectangle-area of small rectangle
=(2x+a)(2x)-x(x+b)
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=3x^2+2xa-bx
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3 years ago
Triangle Proofs Please help
oksian1 [2.3K]

Explanation:

There may be a more direct way to do this, but here's one way. We make no claim that the statements used here are on your menu of statements.

<u>Statement</u> . . . . <u>Reason</u>

2. ∆ADB, ∆ACB are isosceles . . . . definition of isosceles triangle

3. AD ≅ BD

and ∠CAE ≅ ∠CBE . . . . definition of isosceles triangle

4. ∠CAE = ∠CAD +∠DAE

and ∠CBE = ∠CBD +∠DBE . . . . angle addition postulate

5. ∠CAD +∠DAE ≅ ∠CBD +∠DBE . . . . substitution property of equality

6. ∠CAD +∠DAE ≅ ∠CBD +∠DAE . . . . substitution property of equality

7. ∠CAD ≅ ∠CBD . . . . subtraction property of equality

8. ∆CAD ≅ ∆CBD . . . . SAS congruence postulate

9. ∠ACD ≅ ∠BCD . . . . CPCTC

10. DC bisects ∠ACB . . . . definition of angle bisector

4 0
2 years ago
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