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il63 [147K]
3 years ago
15

First (a) simplify the expression and then (b) evaluate the expression for x = -8.

Mathematics
2 answers:
PolarNik [594]3 years ago
4 0

Answer: 4

Step-by-step explanation:

a) Simplied Expresion

2x+5(x-2(2+x))

2x+5(x-4-2x)

2x+5(-x-4)

2x-5x-20

-3x-20

b) x=-8

-3(-8)-20= 4

Elza [17]3 years ago
3 0
A)
2x + 5 [x -2(2+x)]
2x + 5 (x -4 -2x)
2x +5 (-x -4)
2x -5x -20
-3x-20 => answer

B)
-3x -20
-3(-8) -20
24 -20
4 => answer

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(7t-2)-(-3+1)=-3(1-3t) how do you do this?
Sergeu [11.5K]
<h2>Greetings!</h2>

Answer:

t = \frac{3}{2}

Step-by-step explanation:

First, you need to complete the -3 + 1 and then expand the brackets

-3 + 1 = -2

7t -2 - (-2) = -3(1 - 3t)

Now expant the -3(1 - 3t) bracket

-3 * 1 = -3

-3 * -3t = 9t

7t - 2 - -2 = 9t - 3

The two negatives turn positive:

7t - 2 + 2 = 9t - 3

7t = 9t - 3

Move the -3 over to the oposite side, and also move the +7t over to the +9t, making it a negative:

3 = 9t - 7t

3 = 2t

Divide both sides by 2:

t = \frac{3}{2}

So the value of t is \frac{3}{2}


<h2>Hope this helps!</h2>
6 0
4 years ago
PLZ HELP I BEG
wlad13 [49]

Pythagorean theorem(√82)^2 = 9^2 + x^2

x = 1 cm


15^2 = 9^2 + y^2

y = 12 cm. 

12-1 = 11


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6 0
3 years ago
Simplify the fraction 15/45​
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Step-by-step explanation:

7 0
3 years ago
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(4y^2-3y+2)+(5y+12y-4)-(13y^2-6y+20)
Andrews [41]

Answer:

-(9 y^2 - 20 y + 22) or if you need y = 10/9 + (7 i sqrt(2))/9 or y = 10/9 - (7 i sqrt(2))/9

Step-by-step explanation:

Simplify the following:

-(13 y^2 - 6 y + 20) + 4 y^2 + 12 y + 5 y - 3 y - 4 + 2

Grouping like terms, -(13 y^2 - 6 y + 20) + 4 y^2 + 12 y + 5 y - 3 y - 4 + 2 = -(13 y^2 - 6 y + 20) + 4 y^2 + (-3 y + 5 y + 12 y) + (2 - 4):

-(13 y^2 - 6 y + 20) + 4 y^2 + (-3 y + 5 y + 12 y) + (2 - 4)

-3 y + 5 y + 12 y = 14 y:

-(13 y^2 - 6 y + 20) + 4 y^2 + 14 y + (2 - 4)

2 - 4 = -2:

-(13 y^2 - 6 y + 20) + 4 y^2 + 14 y + -2

-(13 y^2 - 6 y + 20) = -13 y^2 + 6 y - 20:

-13 y^2 + 6 y - 20 + 4 y^2 + 14 y - 2

Grouping like terms, 4 y^2 - 13 y^2 + 14 y + 6 y - 20 - 2 = (-13 y^2 + 4 y^2) + (6 y + 14 y) + (-20 - 2):

(-13 y^2 + 4 y^2) + (6 y + 14 y) + (-20 - 2)

4 y^2 - 13 y^2 = -9 y^2:

-9 y^2 + (6 y + 14 y) + (-20 - 2)

6 y + 14 y = 20 y:

-9 y^2 + 20 y + (-20 - 2)

-20 - 2 = -22:

-9 y^2 + 20 y + -22

Factor -1 out of -9 y^2 + 20 y - 22:

Answer: -(9 y^2 - 20 y + 22)

______________________________________________

Solve for y:

-9 y^2 + 20 y - 22 = 0

Divide both sides by -9:

y^2 - (20 y)/9 + 22/9 = 0

Subtract 22/9 from both sides:

y^2 - (20 y)/9 = -22/9

Add 100/81 to both sides:

y^2 - (20 y)/9 + 100/81 = -98/81

Write the left hand side as a square:

(y - 10/9)^2 = -98/81

Take the square root of both sides:

y - 10/9 = (7 i sqrt(2))/9 or y - 10/9 = -(7 i sqrt(2))/9

Add 10/9 to both sides:

y = 10/9 + (7 i sqrt(2))/9 or y - 10/9 = -(7 i sqrt(2))/9

Add 10/9 to both sides:

Answer: y = 10/9 + (7 i sqrt(2))/9 or y = 10/9 - (7 i sqrt(2))/9

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