All categories

3 years ago

2.1grams equals milligrams

Mathematics

1 answer:

Vsevolod [243]3 years ago

3 0

1 gram equals 1000 milligrams

You might be interested in

Trig Help!!

hammer [34]

Answer:

are there any answer choicesss

PLz

Step-by-step explanation:

3 0

3 years ago

Grade 6 math 1. Mr. Carlos bought a T-shirt for ₱ 254.95. Round this off to the nearest peso.

sladkih [1.3K]

Answer:

255

Step-by-step explanation:

254.95

.95 is closest to 255.

254.95...255.

5 0

2 years ago

I need help please lol

butalik [34]

For the ones that are not filled out.

1.150

2.150

3.25

4.5

5.35

4 0

3 years ago

If a rectangle A has sides are three times the length of those rectangle B, how do the areas of the two rectangles compare?

Radda [10]

Answer:

The area of A is nine times the area of B.

Step-by-step explanation:

4 0

3 years ago

Lucy has two star systems left to visit on her voyage, but her ship is running low on fuel. The first system, KA-77, is 12001200

-Dominant- [34]

Answer:

1348 light years.

Step-by-step explanation:

Please find the attachment.

Let x represent the distance between KA-7 and KA-11.

We have been given that the first system, KA-7, is 1200 light years away while the second system, KA-11, is 1700 light years away. Lucy sees an angle of 52 degrees between KA-7 and KA-11.

We can see from our attachment that Lucy, KA-7 and KA-11 forms a triangle and we will use law of cosines to solve for x.

$(AB)^2=(AC)^2+(BC)^2-2(AC)(BC)*cos (C)$

Upon substituting our given values in above formula we will get,

$x^2=1200^2+1700^2-2*1200*1700*cos (52^o)$

$x^2=1440000+2890000-4080000*0.615661475$

$x^2=4330000-2511898.81933008$

$x^2=1818101.18066992$

Let us take square root of both sides of our equation.

$x=\sqrt{1818101.18066992}$

$x=1348.3698234\approx 1348$

Therefore, KA-7 and KA-11 are approximately 1348 light years apart.

6 0

3 years ago