2.1grams equals milligrams

Which type of graph would be best for showing the average yearly bonus amounts for employees in different departments of an IT c

nika2105 [10]

I believe it is C. a histogram
(if it’s not then sorry)

5 0

2 years ago

Determine whether the improper integral converges or diverges, and find the value of each that converges.

Brrunno [24]

Answer:

Converges at -1

Step-by-step explanation:

The integral converges if the limit exists, if the limit does not exist or if the limit is infinity it diverges.

We will make use of integral by parts to determine:

let:

$u=x$ $dv=e^(2x)\cdot{dx}$

$du=dx$ $v=2\cdot{e^(2x)}$

$\int\limits^a_b {u} \, dv = uv -\int\limits^a_b {v} \, du$

$\int\limits^a_b {x\cdot{e^2^x} \, dx =2xe^2^x- \int\limits^a_b {2e^2^x} \, dx$

$\int\limits^a_b {xe^2^x} \, dx = 2xe^2^x-2e^2^x-C$

We can therefore determine that if x tends to 0 the limit is -1

$\lim_{x \to \0} 2xe^2^x-2e^2^x=0-1=-1$

5 0

3 years ago

Four times the sum of three consecutive odd integers is seven hundred sixty-five less than three times the product of the larger

Andre45 [30]

Answer:

The consecutive odd integers are (15, 17, 19) or (-17, -15, -13).

Step-by-step explanation:

Let the three consecutive odd integers be: $x-2,x\ and \ x+2$

The condition given is:

$4[x-2+x+x+2]=3x(x+2)-765$

Solve this for x as follows:

$4[x-2+x+x+2]=3x(x+2)-765\\4\times 3x=3x^{2}+6x-765\\3x^{2}-6x-765=0\\x^{2}-2x-255=0\\x^{2}-17x+15x-255=0\\x(x-17)+15(x-17)=0\\(x-17)(x+15)=0$

If $(x-17)=0$ then the value of x is 17.

The odd numbers are:

$x-2=17-2=15\\x=17\\x+2=17+2=19$

If $(x+15)=0$ then the value of x is -15.

The odd numbers are:

$x-2=-15-2=-17\\x=-15\\x+2=-15+2=-13$

Thus, the consecutive odd integers are (15, 17, 19) or (-17, -15, -13).

7 0

2 years ago

Choose the correct way to write a comparison of seven-twelfths and ten-twelfths.

ra1l [238]

Answer:

ok so lets work this out

Step-by-step : 10/12 is closer to 12 than 7/12 soooo its not any of the ones that have these (:) and 10 is bigger than 7 so its

7/12 < 10/12

3 0

2 years ago

In a large school district, 16 of 85 randomly selected high school seniors play a varsity sport. in the same district, 19 of 67

Mashcka [7]

Answer:

Standard Error of the difference = 0.0695

Step-by-step explanation:

Its given that : In a large school district, 16 of 85 randomly selected high school seniors play a varsity sport

$\implies P_1=\frac{16}{85}\\\\n_1=85$

Also, in the same district, 19 of 67 randomly selected high school juniors play a varsity sport

$\implies P_1=\frac{19}{67}\\\\n_2=67$

Now, finding the standard error of the difference :

$\text{Standard Error = }\sqrt{\frac{P_1(1-P_1)}{n_1}+\frac{P_2(1-P_2)}{n_2}}\\\\\implies \text{Standard Error = }\sqrt{\frac{\frac{16}{85}(1-\frac{16}{85})}{85}+\frac{\frac{19}{67}(1-\frac{19}{67})}{67}}\\\\\implies\text{Standard Error = }0.0695$

Hence, Standard Error of the difference = 0.0695

6 0

3 years ago

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