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VARVARA [1.3K]
3 years ago
14

5 (3x+4)-2x=7x-3 (-2x+11) help

Mathematics
2 answers:
VMariaS [17]3 years ago
6 0
Step one: multiply and divide in order. Step two: add and subtract like terms. Step three: get X alone on one side (what you do to one side you have To do to the other side) Step four: simplify and solve :)
raketka [301]3 years ago
6 0
First×5×3×=15×
2nd 5×4=20
so 15x+20-2x= 13x+20 and the other side of the equation is 7
multiply -3×-2x=6x
multiply -3×11=-33
now rewrite equation
13x+20=6x-33
get values to left side and numbers to right side
13x-6x= -33-20 or 7x = -53
now ÷ by 7 x=8 6/7
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Choose all that give the correct expression for the quantity described. The difference of nine times a number x and the quotient
ohaa [14]

Step-by-step explanation:

We are to get the expression for the following statements;

1) The difference of nine times a number x and the quotient of that number and 5.

The product of nine and a number x is expressed as;

=9 \times x\\= 9x

The quotient of that number and 5.

= \frac{x}{5}

The difference between both expression;

9x - \frac{x}{5}

Hence, the difference of nine times a number x and the quotient of that number and 5 is expressed as 9x - \frac{x}{5}

2) Eight more than the quotient of twelve and a number n

Quotient of twelve and a number n is expressed as:

\frac{n}{12}

Eight more than the resulting function is;

\frac{n}{12}+8

Hence eight more than the quotient of twelve and a number n is expressed as \frac{n}{12}+8

3) The product of a number and the quantity 'six minus the number' plus the quotient of eight and the number.

Let the number be x:

six minus the number is expressed as;

6-x

product of a number x and the quantity 'six minus the number is;

x(6-x)

quotient of eight and the number is;

\frac{8}{x}

Taking the resulting sum of the last two expression

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x(6-x) + 8x

4) Sum of three consecutive even integers. 2x + (2x + 2) + (2x + 4).

Let the first even number be 2x

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the sum of three consecutive even integers is expressed as;

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zavuch27 [327]

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If two figures are similar, then the ratio of the corresponding sides is proportional.

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