5 (3x+4)-2x=7x-3 (-2x+11) help

2 answers:

6 0

Step one: multiply and divide in order. Step two: add and subtract like terms. Step three: get X alone on one side (what you do to one side you have To do to the other side) Step four: simplify and solve :)

raketka [301]3 years ago

6 0

First×5×3×=15×
2nd 5×4=20
so 15x+20-2x= 13x+20 and the other side of the equation is 7
multiply -3×-2x=6x
multiply -3×11=-33
now rewrite equation
13x+20=6x-33
get values to left side and numbers to right side
13x-6x= -33-20 or 7x = -53
now ÷ by 7 x=8 6/7

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The length of a rectangle is 7 more than the width.
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$\\ \: \: \: \: \pink{ \dashrightarrow \: \: \: \: \sf { \underbrace{Area_{(Rectangle)} = Length × Width }}} \\ \\$

On Substituting the required values, we get;

$\\ \: \: \: \: \dashrightarrow \: \: \: \: \sf (x)(x + 7) = 744 \\ \\ \\ \: \: \: \: \dashrightarrow \: \: \: \: \sf {x}^{2} + 7x = 744 \\ \\ \\ \: \: \: \: \dashrightarrow \: \: \: \: \sf {x}^{2} + 7x - 744 = 0 \\ \\ \\ \: \: \: \: \dashrightarrow \: \: \: \: \sf {x}^{2} + 31x - 24x - 744 = 0 \\ \\ \\ \: \: \: \: \dashrightarrow \: \: \: \: \sf x(x + 31) - 24 (x + 31) = 0 \\ \\ \\ \: \: \: \: \dashrightarrow \: \: \: \: \sf (x + 31)(x - 24) = 0 \\ \\ \\ \: \: \: \: \dashrightarrow \: \: \: \: \sf x = 24 \: or \: - 31 \\ \\$