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3 years ago

Someone please help! ATTACHMENT (just the circled one)

Mathematics

1 answer:

Elza [17]3 years ago

6 0

4 (3x+9)-3(5y+7) =11

distribute

12x +36 -15y -21 =11

12x -15y +15 =11

subtract 15 from each side

12x -15y =-4

subtract 12x from each side

-15y= - 12x-4

divide by -15

y = -12/-15 x -4/-15

y = 4/5 x + 4/15

slope = 4/5

y intercept = 4/15

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Step-by-step explanation:

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4 years ago

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3 years ago

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Aloiza [94]

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Give a vector parametric equation for the line through the point (−2,−4,0) that is parallel to the line ⟨−2−3t,1−4t,−5t⟩:

eimsori [14]

The tangent vector for the given line is

T(t) = d/dt ⟨-2 - 3t, 1 - 4t, -5t⟩ = ⟨-3, -4, -5⟩

On its own, this vector points to a single point in space, (-3, -4, -5).

Multiply this vector by some scalar t to get a whole set of vectors, essentially stretching or contracting the vector ⟨-3, -4, -5⟩. This set is a line through the origin.

Now translate this set of vectors by adding to it the vector ⟨-2, -4, 0⟩, which correspond to the given point.

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