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Blizzard [7]
3 years ago
7

Three times the largest of three consecutive even integers is equal to the sum of the other two

Mathematics
1 answer:
slavikrds [6]3 years ago
5 0

Answer:

The three consecutive even integers are

x=-10\\x+2=-8\\x+4=-6

Step-by-step explanation:

Let  

x ----> the smallest of three consecutive even integers

x+2 ----> the second consecutive even integers

x+4 ----> the largest of three consecutive even integers

we know that

Three times the largest of three consecutive even integers is equal to the sum of the other two

so

3(x+4)=x+(x+2)

solve for x

3x+12=2x+2\\3x-2x=2-12\\x=-10

Find (x+2)

(x+2)=-10+2=-8

Find (x+4)

(x+4)=-10+4=-6

therefore

The three consecutive even integers are

x=-10\\x+2=-8\\x+4=-6

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Answer:

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"=NORM.INV(alpha/2,0,1)"

"=NORM.INV(alpha/2,0,1)"

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And we can use the following excel code:

"=NORM.INV(0.95,0,1)"

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Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Part a

P(-z_0.025 < Z < z_0.025)

For this case we want a quantile that accumulates 0.025 of the area on the tails of the normal standard distribution, and for this case we can calculate the z value with the following excel codes:

"=NORM.INV(0.025,0,1)"

"=NORM.INV(0.025,0,1)"

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Part b

P(-z_{\alpha/2} < Z < z_{\alpha/2})

For this case we want a quantile that accumulates \alpha/2 of the area on the tails of the normal standard distribution, and for this case we can calculate the z value with the following excel codes:

"=NORM.INV(alpha/2,0,1)"

"=NORM.INV(alpha/2,0,1)"

Part c

For this case we want to find a value of z that satisfy:

P(Z > z_alpha) = 0.05.

And we can use the following excel code:

"=NORM.INV(0.95,0,1)"

And we got z_{\alpha/2}=1.64

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