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elena-s [515]
3 years ago
12

I don't understand how to do this can someone please help

Mathematics
1 answer:
Margarita [4]3 years ago
3 0
Put x over 1 and start @ -1 on the graph
Then put 2 over 1 and start @ -2 on the graph


Do the same thing with the other graph
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Translate this sentence into an equation. 128 is the product of Donnie's age and 8 . Use the variable d to represent Donnie's ag
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Researchers are investigating whether people who exercise with a training partner have a greater increase, on average, in target
bulgar [2K]

Answer:

1 - If method I is used, population of generalization will include all those people who may have varying exercising habits or routines.  They may or may not have a regular excersing habit.  In his case sample is taken from a more diverse population

2 - Population of generalization will include people who will have similar excersing routines and habits if method II is used since sample is choosen from a specific population

Step-by-step explanation:

Past excercising habits may affect the change in intensity to a targeted excersise in different manner. So in method I a greater diversity is included and result of excersing with or without a trainer will account for greater number of variables than method II.

7 0
3 years ago
5 inches is what fraction of a foot
ipn [44]

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5/12

Step-by-step explanation:

3 0
2 years ago
50+51+52+...+101=...<br>Can you help me? I do not understand
Dmitriy789 [7]

Suppose

S=50+51+52+\cdots+100+101

At the same time, we can write

S^*=101+100+99+\cdots+51+50

Note that S=S^* (just reverse the sum). Let's pair the first terms of S and S^*, and the second, and the third, and so on:

S+S^*=(50+101)+(51+100)+(52+99)+\cdots+(100+51)+(101+50)

Now, each grouped term in the sum on the right side adds to 151. There are 52 grouped terms on that same side (because there are 50 numbers in the range of integers 51-100, plus 50 and 101), which menas

S+S^*=52\cdot151

But S=S^*, as we pointed out, so

2S=52\cdot151\implies S=\dfrac{52\cdot151}2=3926

5 0
3 years ago
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