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ludmilkaskok [199]
4 years ago
7

Why can acceleration include only a change in direction?

Physics
2 answers:
andrew-mc [135]4 years ago
8 0
HEYA!!!!

Here's is the answer.

The statements

A,C,D aren't justified coz

.A change in direction of speed is called velocity.

Which implies that velocity is a vector quantity.
Hence having direction as well as
speed .So,The correct answer seems to be B)

HOPE IT WORKS OUT........

:)

Fynjy0 [20]4 years ago
6 0

First we shall look at some terms:

Velocity - frequency of change of an objects position.

Acceleration - frequency of change of an objects velocity


Since velocity covers both change in direction and speed, we can asume that the answer is B, not because it's the only one we worked with, but because the others don't make any sense:

A - this is not correct, because a chnage in direction can be done withough a change in speed.

C - The scientific definition of acceleration does include speed, and this is not a reasonable answer.

D - Velocity can change, unlike said in the sentence.


Hope it helped,


BioTeacher101

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Answer:

There are 4 Aluminum atoms in 4Al(OH)3.

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Which of the following describes velocity only in terms of metric units?
Lelechka [254]

Choice 'D' describes speed in the metric units 'meter' and 'second'.
With no mention of direction, it can't be called 'velocity'.

8 0
4 years ago
A 2.40 kg ball is attached to an unknown spring and allowed to oscillate. The figure below shows a graph of the ball’s position
irga5000 [103]

(a) The period of the oscillation is 0.8 s.

(b) The frequency of the oscillation is 1.25 Hz.

(c) The angular frequency of the oscillation is 7.885 rad/s.

(d) The amplitude of the oscillation is 3 cm.

(e) The force constant of the spring is 148.1 N/m.

The given parameters:

  • <em>Mass of the ball, m = 2.4 kg</em>

<em />

From the given graph, we can determine the missing parameters.

The amplitude of the wave is the maximum displacement, A = 3 cm

The period of the oscillation is the time taken to make one complete cycle.

T = 0.8 s

The frequency of the oscillation is calculated as follows;

f = \frac{1}{T} \\\\f = \frac{1 }{0.8} \\\\f = 1.25 \ Hz

The angular frequency of the oscillation is calculated as follows;

\omega = 2\pi f\\\\\omega = 2\pi \times 1.25\\\\\omega = 7.855 \ rad/s

The force constant of the spring is calculated as follows;

\omega = \sqrt{\frac{k}{m} } \\\\\omega ^2 = \frac{k}{m} \\\\ k = \omega ^2 m\\\\k = (7.855)^2 \times 2.4\\\\k = 148.1 \ N/m

Learn more about general wave equation here: brainly.com/question/25699025

4 0
3 years ago
The magnetic field inside a 5.0-cm-diameter solenoid is 2.0 T and decreasing at 5.00 T/s. Part A) What is the electric field str
Veronika [31]

Answer:

(A). The electric field strength inside the solenoid at a point on the axis is zero.

(B). The electric field strength inside the solenoid at a point 1.50 cm from the axis is 3.75\times10^{-2}\ V/m.

Explanation:

Given that,

Magnetic field = 2.0 T

Diameter = 5.0 cm

Rate of decreasing in magnetic field = 5.00 T/s

(A). We need to calculate the electric field strength inside the solenoid at a point on the axis

Using formula of electric field inside the solenoid

E=\dfrac{r}{2}|\dfrac{dB}{dt}|

Electric field on the axis of the  solenoid

Here, r = 0

E=\dfrac{0}{2}\times5.00

E = 0

The electric field strength inside the solenoid at a point on the axis is zero.

(B). We need to calculate the electric field strength inside the solenoid at a point 1.50 cm from the axis

Using formula of electric field inside the solenoid

E=\dfrac{r}{2}|\dfrac{dB}{dt}|

E=\dfrac{1.50\times10^{-2}}{2}\times|5.00|

E=0.0375= 3.75\times10^{-2}\ V/m

Hence, (A). The electric field strength inside the solenoid at a point on the axis is zero.

(B). The electric field strength inside the solenoid at a point 1.50 cm from the axis is 3.75\times10^{-2}\ V/m.

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4 years ago
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aev [14]
What about cod my guy which one are we talking ?
7 0
3 years ago
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