Actually, this has little to do with mathematics and geometry but has to do more with logical reasoning. You have two clauses to get a conclusion from. The reasoning is as follows:
Clause 1: <span>Three noncollinear points determine a plane
Clause 2: </span><span>Points S, O, N are noncollinear
</span>Conclusion: Therefore, points S, O and N form a plane.
One possible solution is
f(x) = x^4
g(x) = x-3
Since
f(x) = x^4
f(g(x)) = ( g(x) )^4
f(g(x)) = ( x-3 )^4
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Another possible solution could be
f(x) = x^2
g(x) = (x-3)^2
Because
f(x) = x^2
f(g(x)) = ( g(x) )^2
f(g(x)) = ( (x-3)^2 )^2
f(g(x)) = (x-3)^(2*2)
f(g(x)) = (x-3)^4
A' = (1/2)*A = (8, 0)
B' = (1/2)*B = (12, 6)
C' = (1/2)*C = (6, 8)
The third choice is appropriate.
Answer:
x ≥ -4
Step-by-step explanation:
-3x + 2 ≤ 14
Subtract 2 from each side
-3x+2-2 ≤ 14-2
-3x ≤ 12
Divide each side by -3 . Remember that dividing by a negative flips the inequality.
-3x/-3 ≥12/-3
x ≥ -4