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BaLLatris [955]
3 years ago
14

Noah collected five water samples from local streams. Each sample was the same size, and he collected 4.35 liters of water in al

l. What was the volume of each water sample?​
Mathematics
1 answer:
andriy [413]3 years ago
8 0

Answer:

4.35/5= 0.87 liters

you divide the total by how many to find out what the unit rate is for each sample

Step-by-step explanation:

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Express 2x^2+8x+3 in the form 2(x+p)^2+q
e-lub [12.9K]

Answer:

2(x + 2)² - 5

Step-by-step explanation:

Given

2x² + 8x + 3

To obtain the required form use the method of completing the square.

The coefficient of the x² term must be 1, thus factor 2 out of 2x² + 8x

= 2(x² + 4x) + 3

add/subtract ( half the coefficient of the x- term)² to x² + 4x

= 2(x² + 2(2)x + 4 - 4) + 3

= 2(x + 2)² - 8 + 3

= 2(x + 2)² - 5

with p = 2 and q = - 5

4 0
3 years ago
Josiah is buying a Christmas present for his mom. He has $24 in his saving account but needs $60 to buy the present he has in mi
olchik [2.2K]

Answer:

Step-by-step explanation:

9h + 24 = 60

6 0
2 years ago
The system of equations graphed below has how many solutions?
Artist 52 [7]
Answer: C) 0

The lines are parallel. They never cross. To have a solution, the lines need to intersect. Each intersection is a solution. That's why there are no solutions here. The system is inconsistent.

Note how the slopes are both 1/2 while the y intercepts are different. Parallel lines have equal slopes but different y intercepts.
5 0
3 years ago
Let f(x)=x^3-x-1
alexira [117]
f(x) = x^3 - x - 1

To find the gradient of the tangent, we must first differentiate the function.

f'(x) = \frac{d}{dx}(x^3 - x - 1) = 3x^2 - 1

The gradient at x = 0 is given by evaluating f'(0).

f'(0) = 3(0)^2 - 1 = -1

The derivative of the function at this point is negative, which tells us <em>the function is decreasing at that point</em>.

The tangent to the line is a straight line, so we will have a linear equation of the form y = mx + c. We know the gradient, m, is equal to -1, so

y = -x + c

Now we need to substitute a point on the tangent into this equation to find c. We know a point when x = 0 lies on here. To find the y-coordinate of this point we need to evaluate f(0).

f(0) = (0)^3 - (0) - 1 = -1

So the point (0, -1) lies on the tangent. Substituting into the tangent equation:

y = -x + c \\\\ -1 = -(0) + c \\\\ -1 = c \\\\ \text{Equation of tangent is } \boxed{y = -x - 1}
6 0
3 years ago
Given x less than y, compare the following expressions and determine which is greater: 2x-y;2y-x. Explain your answer
sweet [91]

Let's form the difference of the two expressions and see what we can learn.

(2y -x) -(2x -y) = 2y -x -2x +y = 3y -3x = 3(y -x)

Since y > x, this is positive, so 2y -x is greater than 2x -y.

8 0
3 years ago
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