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Y_Kistochka [10]
3 years ago
7

If an original price is 1,195 and increased to 2,075 what is the percent

Mathematics
1 answer:
Ivenika [448]3 years ago
3 0
|1195 - 2075| = | - 880| = 880
1195 + 2075 = 3270 \div 2 = 1635
\frac{880}{1635} = 0.538226 \times 100 = 53.8226% difference
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THE NUMBER 1-10 ARE IN A BAG, YOU TAKE 2 OUT WITHOUT REPLACEMENT. WHAT IS THE PROBABILITY OF DRAWING THE NUMBER 7 THE FIRST TIME
ehidna [41]

Answer:

1 / 18

Step-by-step explanation:

PROBABILITY OF DRAWING THE NUMBER 7 THE FIRST TIME = Number of favorable outcome / Total number of outcomes

Favorable outcome = 1

Total number of outcome (1,2,3,4,5,6,7,8,9,10) = 10

PROBABILITY OF DRAWING THE NUMBER 7 THE FIRST TIME  = 1 / 10

PROBABILITY OF DRAWING AN EVEN NUMBER THE SECOND TIME = Number of favorable outcome / Total number of outcomes

Favorable outcome (2,4,6,8,10) = 5

Total number of outcomes (1,2,3,4,5,6,8,9,10) = 9

PROBABILITY OF DRAWING AN EVEN NUMBER THE SECOND TIME = 5/9

PROBABILITY OF DRAWING THE NUMBER 7 THE FIRST TIME AND THEN DRAWING AN EVEN NUMBER = 1 / 10  * 5 / 9 = 1 / 18

6 0
3 years ago
NUMBER 27 please!!!!!!!
Artist 52 [7]
The inequality can be:
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3000 \div 150
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3 0
3 years ago
Write the equation of the line that satisfies the given conditions. Express the final equation in standard form.
Anton [14]

Answer:

The equation of line with given points and perpendicular to y-axis is

y = - 7  

Step-by-step explanation:

Given as :

The given points as ( - 10 , - 7)

The equation of line is Y = mX + c

So The line will satisfy given points

Or,  - 7 = m ( -10 ) + c

Now This line is perpendicular to y- axis

∴ The slop of line perpendicular to  y axis is 0

So, - 7= 0 + c

or, c = - 7

∴ Equation of line is y = 0 + c

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Hence The equation of line with given points and perpendicular to y-axis is y = - 7      Answer

8 0
3 years ago
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bazaltina [42]

Answer:

x=2<br/>y=1

Step-by-step explanation:

\left\{ \begin{array} { l } { 4 x + y = 9 } \\ { 3 x - 2 y = 4 } \end{array} \right.

4x+y=9,3x-2y=4

4x+y=9

4x=-y+9

x=\frac{1}{4}\left(-y+9\right)

x=-\frac{1}{4}y+\frac{9}{4}

3\left(-\frac{1}{4}y+\frac{9}{4}\right)-2y=4

-\frac{3}{4}y+\frac{27}{4}-2y=4

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-\frac{11}{4}y=-\frac{11}{4}

y=1

x=\frac{-1+9}{4}

x=2

x=2,y=1

6 0
2 years ago
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