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3 years ago

If an original price is 1,195 and increased to 2,075 what is the percent

1 answer:

3 0

$|1195 - 2075| = | - 880| = 880$
$1195 + 2075 = 3270 \div 2 = 1635$
$\frac{880}{1635} = 0.538226 \times 100$ = 53.8226% difference

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A shipment of 50 precision parts including 4 that are defective is sent to an assembly plant. The quality control division selec

natali 33 [55]

Answer:

0.3968 = 39.68% probability this shipment passes inspection.

Step-by-step explanation:

The parts are chosen without replacement, which means that the hypergeometric distribution is used to solve this question.

Hypergeometric distribution:

The probability of x successes is given by the following formula:

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

In which:

x is the number of successes.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

In this question:

50 parts means that $N = 50$

4 defective means that $k = 4$

10 are chosen, which means that $n = 10$

What is the probability this shipment passes inspection?

Probability that none is defective, so:

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

$P(X = 0) = h(0,50,10,4) = \frac{C_{4,0}*C_{46,10}}{C_{50,10}} = 0.3968$

0.3968 = 39.68% probability this shipment passes inspection.

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3 years ago

How to figure out median weight

statuscvo [17]

They need look a median wieght.

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Both B and D are 3rd degree, but only D is a 3rd degree binomial because it has only 2 terms. The answer is D.

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3 years ago

5r-2=6r+5 what does r equal

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Answer:

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Step-by-step explanation:

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You interview 913 persons and only 5 prefer Cajun food. What percentage prefer Cajun food?

noname [10]

That would be 5/913. As a percent, that would be 0.5%.

I hope this answer helped you! If you have any further questions or concerns, feel free to ask! :)

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3 years ago

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