Rubik's Cubes! I love these things...
There are multiple methods to solving the Rubik's cube. My personal favorite (and the best if you are a beginner) is the F2L method, or First Two Layers. The first half is patterns and placement, the rest of F2L consists of algorithms. There are not enough characters allowed to tell you specifically how to solve the Rubik's cube. However, there is a guy on YouTube who very clearly explains specific methods over how to solve it. His name is Noah Richardson. He is probably one of the best at explaining the cube's complexity into easy to understand terms, for beginners.
Glad to see more people getting interested into the Rubik's Cube again!
Have a good one!
Answer: A= 1/2bh
The b is for base and the h is for height
use cross products to solve
5* (n-9) = 8*n
distribute
5n-45 = 8n
subtract 5n from both sides
-45 = 3n
divide both sides by 3
-15 = n
Answer:
The probability that a random sample of 10 second grade students from the city results in a mean reading rate of more than 96 words per minute
P(x⁻>96) =0.0359
Step-by-step explanation:
<em>Explanation</em>:-
<em>Given sample size 'n' =10</em>
<em>mean of the Population = 90 words per minute</em>
<em>standard deviation of the Population =10 wpm </em>
<em>we will use formula</em>
<em> </em>
<em></em>
<em>Let X⁻ = 96</em>

Z = 1.898
<em>The probability that a random sample of 10 second grade students from the city results in a mean reading rate of more than 96 words per minute</em>
<em></em>
<em></em>
<em> = 1- P( Z ≤z⁻)</em>
<em> = 1- P(Z<1.898)</em>
= 1-(0.5 +A(1.898)
= 0.5 - A(1.898)
= 0.5 -0.4641 (From Normal table)
= 0.0359
<u><em>Final answer</em></u>:-
The probability that a random sample of 10 second grade students from
= 0.0359