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snow_lady [41]
3 years ago
10

A drama club earns $1040 from a production. A total of 64 adult tickets and and 132 student tickets are sold. An adult ticket co

sts twice as much as a student ticket. • write a system of linear equations that represents this situation. • what is the cost of each ticket?
Mathematics
1 answer:
CaHeK987 [17]3 years ago
5 0
A=adult ticket           s=student ticket                         

64a+132s=$1040
 a=2s
128a+132s=$1040
260tickets=$1040
$1040/260=$4
s=$4      (1s=$4x1)
a=$8      (2s=$4x2)

132s=$528       (132x$4)
64a=$512           (64x$8)
TOTAL=$1040 
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Four friends are creating posters for their presentations, which will be delivered in different locations. Which person should c
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Lindsey, who is delivering her speech in a large auditorium

Step-by-step explanation:

Jin, who is delivering her speech to a small group sitting around a table

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8 0
2 years ago
I will mark you brainlist!
Alborosie

Answer:

B. 4, Heads

4, Tails

5, Heads

5, Tails

6, Heads

6, Tails

Step-by-step explanation:

Given that the cube is labelled 1 to 6 and the coin has a head or a tail, the only outcome when the number cube lands on a number greater than 3 means that the cube lands on 4 or 5 or 6.

On the other hand, the coin may give a head or a tail.

In light of this, the possible answers are;

4, Heads

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5, Heads

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6, Heads

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Hence option B is right

7 0
3 years ago
Imagine that you would like to purchase a $275,000 home. Using 20% as
vfiekz [6]

Answer:

The mortgage chosen is option A;

15-year mortgage term with a 3% interest rate because it has the lowest total amount paid over the loan term of $270,470

Step-by-step explanation:

The details of the home purchase are;

The price of the home = $275,000

The mode of purchase of the home = Mortgage

The percentage of the loan amount payed as down payment = 20%

The amount used as down payment for the loan = $55,000

The principal of the mortgage borrowed, P = The price of the house - The down payment

∴ P = $275,000 - 20/100 × $275,000 = $275,000 - $55,000 = $220,000

The principal of the mortgage, P = $220,000

The formula for the total amount paid which is the cost of the loan is given as follows;

Outstanding \ Loan \ Balance = \dfrac{P \cdot \left[\left(1+\dfrac{r}{12} \right)^n -  \left(1+\dfrac{r}{12} \right)^m \right] }{1 - \left(1+\dfrac{r}{12} \right)^n }

The formula for monthly payment on a mortgage, 'M', is given as follows;

M = \dfrac{P \cdot \left(\dfrac{r}{12} \right) \cdot \left(1+\dfrac{r}{12} \right)^n }{\left(1+\dfrac{r}{12} \right)^n - 1}

A. When the mortgage term, t = 15-years,

The interest rate, r = 3%

The number of months over which the loan is payed, n = 12·t

∴ n = 12 months/year × 15 years = 180 months

n = 180 months

The monthly payment, 'M', is given as follows;

M =

The total amount paid over the loan term = Cost of the mortgage

Therefore, we have;

220,000*0.05/12*((1 + 0.05/12)^360/( (1 + 0.05/12)^(360) - 1)

M = \dfrac{220,000 \cdot \left(\dfrac{0.03}{12} \right) \cdot \left(1+\dfrac{0.03}{12} \right)^{180} }{\left(1+\dfrac{0.03}{12} \right)^{180} - 1}  \approx 1,519.28

The minimum monthly payment for the loan, M ≈ $1,519.28

The total amount paid over loan term, A = n × M

∴ A ≈ 180 × $1,519.28 = $273,470

The total amount paid over loan term, A ≈ $270,470

B. When t = 20 year and r = 6%, we have;

n = 12 × 20 = 240

\therefore M = \dfrac{220,000 \cdot \left(\dfrac{0.06}{12} \right) \cdot \left(1+\dfrac{0.06}{12} \right)^{240} }{\left(1+\dfrac{0.06}{12} \right)^{240} - 1}  \approx 1,576.15

The total amount paid over loan term, A = 240 × $1,576.15 ≈ $378.276

The monthly payment, M = $1,576.15

C. When t = 30 year and r = 5%, we have;

n = 12 × 30 = 360

\therefore M = \dfrac{220,000 \cdot \left(\dfrac{0.05}{12} \right) \cdot \left(1+\dfrac{0.05}{12} \right)^{360} }{\left(1+\dfrac{0.05}{12} \right)^{360} - 1}  \approx 1,181.01

The total amount paid over loan term, A = 360 × $1,181.01 ≈ $425,163

The monthly payment, M ≈ $1,181.01

The mortgage to be chosen is the mortgage with the least total amount paid over the loan term so as to reduce the liability

Therefore;

The mortgage chosen is option A which is a 15-year mortgage term with a 3% interest rate;

The total amount paid over the loan term = $270,470

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3 years ago
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When we have exponents like such (x^-6)^-2 , the numbers are multiplying, so we have x^12, then we take that value and, because it is dividing with the same base, we substract the numbers, so x^12-(-4) = x^16.

5 0
3 years ago
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