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sergeinik [125]
2 years ago
11

Help me please i don’t get it

Mathematics
1 answer:
Fofino [41]2 years ago
7 0

Answer:

4

Step-by-step explanation:

Both triangles are the same shape, just to different scales. In order to find out the length of side AB in triangle ABC, you have to find out the length of side PQ in triangle PQR and how much bigger than side AB is.

You can tell that sides AC and PR are similar, and 30/5 is 6. You see also that sides BC and QR are similar, and 42/7 is also 6. We have now discovered that triangle PQR is 6 times bigger than triangle ABC.

So now, to find the length of the missing side, we have to shrink side PQ by 6.  24/6 is 4. Therefore, the length of side AB is 4.

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12a + 8b....common factor is 4
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Find the unknown side length for ABC.<br> A.) 483.86<br> B.) 171.36<br> C.) 13.09
Allushta [10]
It’s b I just had this
3 0
3 years ago
Read 2 more answers
Guys help me please
Svetlanka [38]
I think your answers are a b and c but I’m not exactly sure, sorryy:)
7 0
3 years ago
I need help with these questions.
Ivanshal [37]

Answer:

  • See below

Step-by-step explanation:

<h3>Q13</h3>

The greater the angle the greater the opposite side

<u>Sides in ascending order:</u>

  • AB = 17, AC = 18, BC = 21

<u>Angles in same order</u>

  • ∠C, ∠B, ∠A
<h3>Q14</h3>

<u>As above, sides in ascending order:</u>

  • AB = 15, AC = 16, BC = 17

<u>Angles in same order</u>

  • ∠C, ∠B, ∠A
<h3>Q15</h3>

<u>Exterior angle equals to sum of non-adjacent interior angles</u>

  • 142° = x + 66°
  • x = 142° - 66°
  • x = 76°
<h3>Q16</h3>

<u>Same subject and isosceles triangle:</u>

  • x + x = 158°
  • 2x = 158°
  • x = 79°
<h3>Q17</h3>

<u>Same subject</u>

  • m∠QSR = m∠QPS + m∠PQS
  • 2x = x + m∠PQS
  • m∠PQS = 2x - x
  • m∠PQS = x

ΔPQS has two angles with the measure of x, hence their opposite sides are congruent and the triangle is isosceles

7 0
2 years ago
1. In how many different ways can 5 people be seated at a round table?
Alexeev081 [22]
1. 

Assume the people A, B, C, D and E are sitting in a row.

since there are 5 positions, they can sit in 5*4*3*2*1=120 ways.

consider 1 certain sitting position, for example ABCDE, that is B has A to his right, C to his left. D has C to his right and E to his left. And so on.

the positions 

ABCDE
BCDEA
CDEAB
DEABC
EABCD

while in a row are different positions, in a round table they are the same thing.

(read the letters starting from A, and when the letters finish, continue reading from the beginning of the row. They all read "ABCDE")

This means that any arrangement in a round table, is converted to 5 arrangements in a row.

So there are in total  \frac{5!}{5}=4*3*2*1=24 arrangements of 5 people around a table.

2. check picture.

Consider the case where A is at (2, 2) and B is at (5, 6)

A can move to B through 3 horizontal units to the right, we call them E (for East) and 4 vertical units up, which we call N (for north).

the total path is 7 units.

it can be done in several ways, for example:

ENNNENE (the red path shown in the figure)
NNEEENN (the black path shown in the figure)

In total there are 
\frac{7!}{3!*4!}= \frac{7*6*5*4!}{3!*4!}= \frac{7*6*5}{3!}= 35 paths.

Remark: 7! is the number of arrangements if the letters were different. We divide by 3! because of the 3 E's and 4! because of the 4 N's. 

Another possibility could be A'(3, -5), B'(8,-3).

From A' to B' we go by a total of 5 E and 2 N, so there are 

\frac{7!}{2!*5!}= \frac{7*6*5!}{2!*5!}= \frac{7*6}{2}= 42 paths in total.
there is one more possibility
\frac{7!}{1!(6!)}=7

C.

a) consider the letters {V,E,C,T,O,R}

we can form 6*5*4*3*2*1=720 words, as the first digit can be any of the 6 letters, combined with 5 for the second letter and so on.

b) the difference with a is that we have 5 letters and we have 2 T.

we have in total 5*4*3*2*1=120 arrangements of these letters, if the 2 T's were considered as separate.

consider the arrangements:

T_1RUST_2 and T_2RUST_1.

We read bth as just TRUST, but the permutation formula 5*4*3*2*1 considers these as 2 different.

this is why we need to divide 120 by 2, to get the actual number of words that can be formed. So the number is 60.

Answers:

1) 24

2) 7, 35 or 42. it depends on the positions of A and B, check the solution

3) a-720, b-160
 

8 0
3 years ago
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