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Serga [27]
3 years ago
10

The limit as x approaches 1 from the left, with the square root of x minus 1 over x minus 1

Mathematics
1 answer:
EastWind [94]3 years ago
4 0
Hello here is a solution :

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Jet001 [13]
Hey dude we’re both from Nepal so here’s the written worksheet hope it helps :)

6 0
2 years ago
Let a and b be real numbers were a≠ b ≠ 0. Which of the following functions could represent the graph below?
wlad13 [49]

Answer:

A

Step-by-step explanation:

where the graph

WHERE THE GRAPH???

8 0
2 years ago
How do you find a surface area of a rectangular prism?
n200080 [17]
Use the equation
A= 2(wl +hl +hw)

Where
w is width
h is height
l is length
4 0
3 years ago
HELP I NEED HELP ASAP HELP I NEED HELP ASAP HELP I NEED HELP ASAP HELP I NEED HELP ASAP
vredina [299]

Answer:

D

Step-by-step explanation:

I hope this is correct!

8 0
3 years ago
Given: ABCD is a trapezoid, AC ⊥ CD AB = CD, AC=the square root of 75 , AB = 5 Find: AABCD
Ugo [173]

In this attached picture according to the conditions of the problem we have an isosceles trapezoid and since we know that legs are equal (AD=BC=5 cm), we have to calculate bases and height in order to find the area. Working with the triangle BCD, we apply Pythagoras theorem and find that CD = \sqrt{75+25} = 10 cm. Since BDC is a right triangle, applying theorem for the area of triangles, we find that \frac{1}{2} * BF =  \frac{1}{2} * 5 * \sqrt{75} and BF= 0.5\sqrt{75}. Since ABCD is an isosceles trapezoid, triangles ADE and BFC are congruent with Angle Side Angle theorem. Then, DE=FC and with the help of Pythagoras theorem, DE=FC=2.5 cm. Then, AB=EF=5 cm and the area of the trapezoid is  A= BF *  \frac{AB+CD}{2} = 0.5  \sqrt{75}  * \frac{5+10}{2} = 18.75 \sqrt{3}   cm^{2}

3 0
3 years ago
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