Suppose a normal distribution has a mean of 98 and a standard deviation of 6. What is P(x< or = to 110)
1 answer:
Answer:
97.8%
Step-by-step explanation:
110 is 2 standard deviations above the mean (6+6 = 12)
12+98 = 110
Looking at the standard deviation curve
P(x< or = to 110) = 1 - P(x>110)
We can find the probability that x>100 by adding anything above 2 standard deviations above the curve.
P(x>110) = 2.1+.1 = 2.2%
P(x< or = to 110) = 1 - P(x>110)
= 1- 2.2%
= 1- .022
= .978
= 97.8 %
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