Answer:
Option B
Step-by-step explanation:
Given
Two Data sets
Class A :{ 2, 5, 7, 6, 4, 3, 8, 7, 4, 5, 7, 6, 3, 5, 4, 2, 4, 6, 3, 5}
Class B : {3, 7, 6, 4, 3, 2, 4, 5, 6, 7, 2, 2, 2, 3, 4, 5, 2, 2, 5, 6}
In order to check the options we will have to find the mean and median of both data sets.
So for Class A:
Mean= x =(Sum of values)/(Number of values)
=96/20
=4.8
For median the data has to be arranged in ascending order, so
2, 2,3,3,3,4,4,4,4,5,5,5,5,6,6,6,7,7,7,8
Median will be the average of middle two values as the number of items are odd.
Median=(5+5)/2
=10/2
=5
Range = 8-2 = 6
For Class B:
Mean= x =(Sum of values)/(Number of values)
=80/20
=4
For median, arranging the values
2,2,2,2,2,2,3,3,3,4,4,4,5,5,5,6,6,6,7,7
Median=(4+4)/2
=8/2
=4
Range = 7-2 = 5
We get,
Mean of class A > Mean of Class B
Median of Class A > Median of Class B
Range of Class A > Range of Class B
We observe that only option B is correct for the given data sets..
