50, 0 ,|-50|
I don’t really have an explanation but that’s the answer
Answer:
$115.36
Step-by-step explanation:
Given data
P=$103
r=1.9%
t= 6 years
The expression for the amount is given as

substitute


Hence the final amount is $115.36
Answer:
For a monthly cost of at least $7 and at most $8, you can have between 100 and 110 calling minutes.
Step-by-step explanation:
The problem states that the monthly cost of a celular plan is modeled by the following function:

In which C(x) is the monthly cost and x is the number of calling minutes.
How many calling minutes are needed for a monthly cost of at least $7?
This can be solved by the following inequality:






For a monthly cost of at least $7, you need to have at least 100 calling minutes.
How many calling minutes are needed for a monthly cost of at most 8:






For a monthly cost of at most $8, you need to have at most 110 calling minutes.
For a monthly cost of at least $7 and at most $8, you can have between 100 and 110 calling minutes.
Answer:
Step-by-step explanation:
