Answer:
first explain what you need help with specifically then maybe people can help, to bland of a question
answered
There are 50 deer in a particular forest. The population is increasing at a rate of 15% per year. Which exponential growth function represents
the number of deer y in that forest after x months? Round to the nearest thousandth.
1
SEE ANSWER
ADD ANSWER
+5 PTS
fanniemurphy is waiting for your help.
Add your answer and earn points.
Answer
1.0/5
1
dribeiro
Ace
697 answers
561.4K people helped
Answer:
The expression that represents the number of deer in the forest is
y(x) = 50*(1.013)^x
Step-by-step explanation:
Assuming that the number of deer is "y" and the number of months is "x", then after the first month the number of deer is:
y(1) = 50*(1+ 0.15/12) = 50*(1.0125) = 50.625
y(2) = y(1)*(1.0125) = y(0)*(1.0125)² =51.258
y(3) = y(2)*(1.0125) = y(0)*(1.0125)³ = 51.898
This keeps going as the time goes on, so we can model this growth with the equation:
y(x) = 50*(1 - 0.15/12)^(x)
y(x) = 50*(1.013)^x
Answer:
Step-by-step explanation:
The MAD is 2.
Answer:
Step-by-step explanation:
Line equation is given as y = mx + b
Where, m is the slope of the line, which is,
b is the y-intercept. It is the point at which the line crosses the y-axis for which the value of x = 0.
=>Find m and b to derive an equation for the line.
using the 2 coordinate pairs, (1, 5), (-1, -5),
Let, x2 = -1,
x1 = 1,
y2 = -5,
y1 = 5
From the graph given, the line intercepts the y-axis at point 0. Therefore b = 0.
Plug in the values of m and b in the line of equation.
y = mx + b
y = 5x + 0
y = 5x
Therefore, the equation of the line, in the graph above, written in slope-intercept form is:
