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77julia77 [94]
3 years ago
12

Please help I keep getting it wrong and I can't move on to the next part! You need to look at both pictures to answer this.

Mathematics
1 answer:
KIM [24]3 years ago
8 0

Explanation:

3. ∠2 and ∠3 are a linear pair → definition of a linear pair

4. ∠3 and ∠4 are a linear pair → definition of a linear pair

5. m∠2 +m∠3 = 180° → definition of a linear pair (or angle addition postulate)

6. m∠3 +m∠4 = 180° → definition of a linear pair (or angle addition postulate)

7. m∠2 +m∠3 = m∠3 +m∠4 → substitution property

8. m∠2 = m∠4 → subtraction property

9. ∠2 ≅ ∠4 → definition of congruent angles

_____

A pair of angles is a "linear pair" if they are adjacent and supplementary. ∠2 and ∠3 are adjacent and the non-common legs form a straight line. It isn't clear what your definition of linear pair is and what you need to do to claim that the angles sum to 180°. Above, we have assumed a definition of "linear pair" that includes the facts that → they sum to 180°; → non-adjacent sides form a straight line.

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Three populations have proportions 0.1, 0.3, and 0.5. We select random samples of the size n from these populations. Only two of
IRINA_888 [86]

Answer:

(1) A Normal approximation to binomial can be applied for population 1, if <em>n</em> = 100.

(2) A Normal approximation to binomial can be applied for population 2, if <em>n</em> = 100, 50 and 40.

(3) A Normal approximation to binomial can be applied for population 2, if <em>n</em> = 100, 50, 40 and 20.

Step-by-step explanation:

Consider a random variable <em>X</em> following a Binomial distribution with parameters <em>n </em>and <em>p</em>.

If the sample selected is too large and the probability of success is close to 0.50 a Normal approximation to binomial can be applied to approximate the distribution of X if the following conditions are satisfied:

  • np ≥ 10
  • n(1 - p) ≥ 10

The three populations has the following proportions:

p₁ = 0.10

p₂ = 0.30

p₃ = 0.50

(1)

Check the Normal approximation conditions for population 1, for all the provided <em>n</em> as follows:

n_{a}p_{1}=10\times 0.10=1

Thus, a Normal approximation to binomial can be applied for population 1, if <em>n</em> = 100.

(2)

Check the Normal approximation conditions for population 2, for all the provided <em>n</em> as follows:

n_{a}p_{1}=10\times 0.30=310\\\\n_{c}p_{1}=50\times 0.30=15>10\\\\n_{d}p_{1}=40\times 0.10=12>10\\\\n_{e}p_{1}=20\times 0.10=6

Thus, a Normal approximation to binomial can be applied for population 2, if <em>n</em> = 100, 50 and 40.

(3)

Check the Normal approximation conditions for population 3, for all the provided <em>n</em> as follows:

n_{a}p_{1}=10\times 0.50=510\\\\n_{c}p_{1}=50\times 0.50=25>10\\\\n_{d}p_{1}=40\times 0.50=20>10\\\\n_{e}p_{1}=20\times 0.10=10=10

Thus, a Normal approximation to binomial can be applied for population 2, if <em>n</em> = 100, 50, 40 and 20.

8 0
3 years ago
A window in Michael's room is the shape of a trapezoid. The bases are 30 inches and 40 inches. The height of the window is 24 in
lana [24]

Answer:

The area of the window is of 840 square inches.

Step-by-step explanation:

To find the area of an trapezoid, we need to add the sum of the bases, multiply by the height, and then divide by 2.

Matematically:

A = \frac{(b_{1} + b_{2})*h}{2}

In which b_{1} and b_{2} are the bases and h is the height.

In this question:

b_{1} = 30, b_{2} = 40, h = 24

All the measures in inches, so the area is in square inches.

A = \frac{(30 + 40)*24}{2} = 840

The area of the window is of 840 square inches.

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3 years ago
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sergij07 [2.7K]

Answer:

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Paha777 [63]

Answer:

yes it is ill explain

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The student should have added 4 to all parts (left, middle, and right) to get 6 < -3x < 9.

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The student should not have switched the direction of the sign in the final step.

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Step 3: Multiplication property

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If x < 5 and x > c, give a value of c such that there are no solutions to the compound inequality. Explain why there are no solutions

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8 0
3 years ago
Read 2 more answers
Solve pls brainliest
Goshia [24]

Answer:

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4.5341 is closer to 0 than 6.96 is.

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