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densk [106]
3 years ago
12

Solve pls brainliest

Mathematics
1 answer:
Goshia [24]3 years ago
8 0

Answer:

4.5341 < 6.9 < 6.906 < 6.96

Step-by-step explanation:

4.5341 is closer to 0 than 6.96 is.

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Solve each system by substitution.<br> 1) y = 2x + 2<br> y = -5x + 16
dalvyx [7]

Answer:

y = 6

x = 2

Step-by-step explanation:

rearrange the first equation in terms of x

x = (y - 2)/2

substiute x in the second equation

y = -5[(y-2)/2] +16

Now simpilify and solve for y

y = (-5y + 10)/2 +16

y = -5/2y + 5 + 16

y + 5/2y = 5 + 16

3.5y = 21

y = 6

Now substitue y in the first equation to solve for x

x = (6 - 2)/2

x = 2

5 0
3 years ago
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A multiplication table. In the row labeled 3, the numbers 3, 6, 9, 12, 15, 18, 21, 23, and 27 are highlighted. In the row labele
kondaur [170]

Answer:

24:27

Step-by-step explanation:

i got it right on my unit test :)

3 0
3 years ago
Use the model to solve the percent problem.
luda_lava [24]
30 is 20% of the number 150
4 0
3 years ago
Please help I don't know the median give an answer and explanation
morpeh [17]

Answer:

Median is the middle of the data set. For example this data set is 4, 6, 7, 9, 10. First you take out 4 and 10. The you take out 6 and 9 to get a median of 7. But if there is an even amount of numbers like in this data set, 1, 2, 4, 5. Then you take out 1 and 5 and then find the middle point in between 2 and 4 which is 3.

5 0
2 years ago
ASAP I NEED HELP
alexdok [17]

The vertex of this parabola is at (3,-2). When the x-value is 4, the y-value is 3: (4,3) is a point on the parabola. Let's use the standard equation of a parabola in vertex form:

y-k = a(x-h)^2, where (h,k) is the vertex (here (3,-2)) and (x,y): (4,3) is another point on the parabola. Since (3,-2) is the lowest point of the parabola, and (4,3) is thus higher up, we know that the parabola opens up.

Substituting the given info into the equation y-k = a(x-h)^2, we get:

3-[-2] = a(4-3)^2, or 5 = a(1)^2. Thus, a = 5, and the equation of the parabola is

y+2 = 5(x-3)^2 The coefficient of the x^2 term is thus 5.

7 0
3 years ago
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